Answer:
Initial velocity, u = 23.33 m/s
Explanation:
Given the following data;
Acceleration = 2.5 m/s²
Distance = 4 km to meters = 4000 meters
Time = 0.8 mins to seconds = 0.8 * 60 = 48 seconds.
To find the initial velocity, we would use the second equation of motion;

Where;
S represents the displacement or height measured in meters.
u represents the initial velocity measured in meters per seconds.
t represents the time measured in seconds.
a represents acceleration measured in meters per seconds square.
Substituting into the equation, we have;
4000 = u*48 + ½*2.5*48²
4000 = 48u + 1.25*2304
4000 = 48u + 2880
48u = 4000 - 2880
48u = 1120
Initial velocity, u = 1120/48
Initial velocity, u = 23.33 m/s
For a pipe open at both ends, fund frequency (Fo) given byFo = v /2L
v = velocity of sound = 340 m/s (at about 20ºC)
Fo = 340/2*5.34 = 31.8 Hz
While for the one closed at one end and open at the other end...
For a pipe open at one end, fund frequency (Fo) given byFo = v/4L
Fo = 340/4*5.34= 15.9 Hz