What is the chemical formula for a compound between Al and S?

What do destructive forces do

mrs_skeptik [129]

Answer:

they destroy or break stuff i think lol hope this helps

Explanation:

6 0

2 years ago

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Arrange the elements in order of increasing atomic radlus. Use the periodic table

nlexa [21]

Largest to smallest: barium, calcium, selenium, oxygen

3 0

2 years ago

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Enter your answer in the provided box. The atomic masses of 63Cu (69.17 percent) and 65Cu (30.83 percent) are 62.94 and 64.93 am

dybincka [34]

Answer: The average atomic mass of copper is 63.55 amu.

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

For $_{29}^{63}\textrm{Cu}$ isotope:

Mass of $_{29}^{63}\textrm{Cu}$ isotope = 62.94 amu

Percentage abundance of $_{29}^{63}\textrm{Cu}$ = 69.17 %

Fractional abundance of $_{29}^{63}\textrm{Cu}$ isotope = 0.6917

For $_{29}^{65}\textrm{Cu}$ isotope:

Mass of $_{29}^{65}\textrm{Cu}$ isotope = 64.93 amu

Percentage abundance of $_{29}^{65}\textrm{Cu}$ = 30.83 %

Fractional abundance of $_{29}^{65}\textrm{Cu}$ isotope = 0.3083

Putting values in equation 1, we get:

$\text{Average atomic mass of Copper}=[(62.94\times 0.6917)+(64.93\times 0.3083)]\\\\\text{Average atomic mass of copper}=63.55amu$

Hence, the average atomic mass of copper is 63.55 amu.

4 0

2 years ago

An important reaction in the formation of photochemical smog is the photodissociation of NO2: NO2 + hv >>> NO(g) + O(g)

vaieri [72.5K]

Explanation:

$NO_2 + hv\rightarrow NO(g) + O(g)$

The maximum wavelength of light that can cause this reaction is 420 nm.

a) The wavelength given lies in the range of visible light range that is from 400 nano meters to 700 nano meters.

The light with wavelength of 420 nm is found in the range of visible light.

b)The maximum strength of a bond :

$E=\frac{h\times c}{\lambda}$

where,

E = energy of photon = Energy required to break single molecule of nitrogen dioxide

h = Planck's constant = $6.626\times 10^{-34}Js$

c = speed of light = $3\times 10^8m/s$

$\lambda$ = wavelength = $420 nm=420\times 10^{-9}m$

$E=\frac{6.626\times 10^{-34}Js\times 3\times 10^8 m/s}{420\times 10^{-9}m}$

$E=4.733\times 10^{-19} J$

Energy required to break 1 mole of nitrogen dioxide molecules:

$= E\times N_A=4.733\times 10^{-19} J\times 6.022\times 10^{23} mol^{-1}$

$=285,012.66 J/mol=285.13 kJ/mol$

(1 J = 0.001 kJ )

285.13 is the maximum strength of a bond, in kJ/mol, that can be broken by absorption of a photon of 420-nm light.

c) the photodissociation reaction showing Lewis-dot structures is given in an image attached.

6 0

3 years ago

Caroline decided to investigate the digestion of starch in the mouth. she smashed up a cracker and placed equal amounts of it in

lys-0071 [83]

I think the answer is fats

3 0

3 years ago