Answer:
The first step in the free radical mechanism for the preparation of polyethylene is:
b. heating an organic peroxide to break the O-O bond
Explanation:
The preparation of ethylene occur by free radical mechanism , which occurs in three steps :
1. Chain Initiation
2. Chain propagation
3. Chain termination.
The first step i.e chain initiation require a radical. The compound are generally peroxide(O-O linkage) that produce radical is :
Benzoyl Peroxide
This compound when heated (with U.V radiation) produce two species of radicals .
(see the attached image)
These RADICALS are highly unstable and very reactive in nature.
They readily react with ethene and initiate the polymerisation.
Thus,
The first step in the free radical mechanism for the preparation of polyethylene is:
b. heating an organic peroxide to break the O-O bond
<u><em>The sequence of Polymerisations are:</em></u>
b. heating an organic peroxide to break the O-O bond
d. propagation of the free radicals
Answer:
It’s the 3 one
Explanation:
Also I think it’s suppose to be
a
b
c
d
From the information presented in the question, the number of molecules present of water present is obtained 2.41 × 10^21 molecules.
From the information we have;
Volume of the damp air = 1 L
Pressure of the damp air = 741.0 torr or 0.975 atm
Temperature of the gas = 20 oC + 273 = 293 K
R = 0.082 atm LK-1mol-1
Number of moles = ?
n =PV/RT
n = 0.975 × 1/0.082 × 293
n = 0.041 moles
Volume of water vapor = 1 L
Temperature of water = -10 oC + 273 = 263 K
Pressure of the gas = 607.1 torr or 0.799 atm
R = 0.082 atm LK-1mol-1
n= PV/RT
n = 0.799 × 1/ 0.082 × 263
n = 0.037 moles
Number of moles of water = 0.041 moles - 0.037 moles = 0.004 moles
If 1 mole = 6.02 × 10^23 molecules
0.004 moles = 0.004 moles × 6.02 × 10^23 molecules/1 mole
= 2.41 × 10^21 molecules
Learn more: brainly.com/question/2510654
I believe KI is not a a binary molecule.
Your welcome
Okay for 8 it is the maximum levels will be higher and for 9 is poor circulation leads to lack of nutrients and oxygen
