3 years ago

HELP ME I AM EXTREMELY DESPERATE!!!!!!

Physics

2 answers:

Nikolay [14]3 years ago

5 0

Answer: B is the correct answer because they are both showing a constant speed

Explanation:

alexandr402 [8]3 years ago

4 0

Answer: C is the correct answer

Explanation:

You might be interested in

A car engine applies a force of 65,000 N, how much work is done by the engine as it pushed a car a distance of 75 m?

kupik [55]

Answer:

$workdone = force \times distance \\ = 65000 \times 75 \\ = 4,875,000 \: J$

3 0

3 years ago

A person spins a tennis ball on a string in a horizontal circle (so that the axis of rotation is vertical). At the point indicat

Ilya [14]

Answer:

direction does the axis of rotation tilt toward after the blow is the z- direction

Explanation:

This is because

Due to the blow, there is a impulse imparted on the ball which gives a change in linear momentum () in the x direction

Thus When cross product of momentum in x direction is taking with r vector, we will get resultant in z direction. Hence change in angular momentum will be z direction.

5 0

3 years ago

3.25 kcal is the same amount of energy as

PIT_PIT [208]

8 0

3 years ago

Read 2 more answers

The body contains many small currents caused by the motion of ions in the organs and cells. Measurements of the magnetic field a

RoseWind [281]

Answer:

270 μA

Explanation:

Use the magnetic field due to long, straight wire and solve for current I.

$B= \frac{\mu_0I}{2\pi r}$

$I= \frac{2\pi r B}{\mu_0}$

plug in the values

$I= \frac{2\pi(5.40\times10^{-2})\times10\times10^{-6}\times10^{-4}}{4\pi\times10^{-7}}$

= 2.7×10^{-4)×10^6

=270 μA

The current that flows in the heart is 270 μA

8 0

3 years ago

A Nichrome wire 44 cm long and 0.30 mm in diameter is connected to a 3.1 V flashlight battery. What is the electric field inside

Alexeev081 [22]

Answer:

7.05 Volts/m

Explanation:

L = length of the Nichrome wire = 44 cm = 0.44 m

V = Potential difference across the end of the wire = battery voltage = 3.1 Volts

E = magnitude of electric field inside the wire

Magnitude of electric field inside the wire is given as

$E = \frac{V}{L}$

Inserting the values

$E = \frac{3.1}{0.44}$

E = 7.05 Volts/m

4 0

3 years ago