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2 years ago

14

HELP ME I AM EXTREMELY DESPERATE!!!!!!

2 answers:

Nikolay [14]2 years ago

5 0

Answer: B is the correct answer because they are both showing a constant speed

Explanation:

alexandr402 [8]2 years ago

4 0

Answer: C is the correct answer

Explanation:

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Explain the bending of light as a property of a warping of space

saveliy_v [14]

Explanation:

According to the general theory of relativity, spacetime curves due to the energy it contains. Since mass is a form of energy, "create" gravity. That is, gravity is the effect observed as a consequence of the curvature of spacetime. Therefore, gravity curves the path of light because it curves the space through which light passes.

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3 years ago

What causes the amount of gravitational force to change?

Ivanshal [37]

The mass of water moving around on Earth’s surface causes the amount of gravitational force.

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2 years ago

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You and your friend are going bungee jumping! You wait directly below them with a camera. When they leap from the bridge they be

Alex

Answer:

The amplitude is $A = 90.2 \ m$

Explanation:

From the question we are told that

The frequency of when sound is approaching observer is $f = 392 Hz$

The frequency as the move away from observer is $f_ a = 330 \ Hz$

The time between the pitch are $t = 10 \ s$

Here you are the observer and your friends are the source of the sound

The period is mathematically evaluated as

$T = 2 t$

as it is the time to complete one oscillation which from on highest pitch to the next highest pitch

Now T can also be mathematically represented as

$T = \frac{2 \pi}{w}$

Where $w$ is the angular velocity

=> $\frac{2 \pi}{w} = 2 * 10$

=> $w = 0.314 \ rad/sec$

Now using Doppler Effect,

The source of the sound is approaching the observer

The

$f = f_o (\frac{v}{v- wA} )$

$392 = f_o (\frac{v}{v- wA} )$

Where A is the amplitude

So when the source is moving away from the observer

$f_a = f_o (\frac{v}{v+ wA} )$

$330 = f_o (\frac{v}{v+ wA} )$

Here $f_o$ is the fundamental frequency

Dividing the both equation we have

$\frac{392}{330} = \frac{f_o(\frac{v}{v-wA} )}{f_o(\frac{v}{v+wA}}$

$1.1878 = \frac{v+wA}{v-wA}$

$1.1878 v - 1.1878 wA = v+wA$

$1.1878 v = 2.1878 wA$

=> $A = \frac{(0.1878 * (330))}{(2.1878)* (0.314)}$

$A = 90.2 \ m$

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3 years ago

Find the magnitude of the resultant forces 6N and 8N inclined at an angle 240° to each<br>other.

Nana76 [90]

Answer:

F = 7.2N

Explanation:

The resultant of two forces acting at some angle is given by using the vector addition as given below

F =√F1^2+F2^2+2F1F2cosθ

Where F1 = 6N and F2 = 8N

θ = 240°

Substituting the values into the equation above

F = √ 6^2+8^2+ 2(6×8)cos240

F =√ 36+64+96cos240

F = √ 100+96 ×-0.5

F = √ 100-48

F = √ 52

F = 7.211

F = 7.2N

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3 years ago

Chris is about to do an experiment to measure the density of water at several temperatures. His teacher has him prepare and sign

Marina86 [1]

Inspect the glassware for cracks or chips prior to beginning the lab.

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