Answer:
team A - team B = 450 N - 415 N
= 35 N
Explanation:
net force on the rope is 35 N and the direction is towards A.since the two teams are pulling away from each other with the given forces, the net force can be calculated by subtracting the forces.
Answer:
(a) The magnitude of the electric dipole moment is 1.68 x 10⁻¹⁴ C.m
(b) The difference between the potential energies ΔU, is 4.6704 x 10⁻¹¹ J
Explanation:
Given;
magnitude of charge, q = 2 nC = 2 x 10⁻⁹ C
distance of separation, d = 8.4 μm = 8.4 x 10⁻⁶ m
strength of electric field, E = 1390 N/C
(a) the magnitude of the electric dipole moment
p = qd
p = (2 x 10⁻⁹ C)(8.4 x 10⁻⁶ m)
p = 1.68 x 10⁻¹⁴ C.m
(b) the difference between the potential energies for dipole orientations parallel and anti-parallel to E
ΔU = U(180) - U(0)
ΔU = 2pE
ΔU = 2(1.68 x 10⁻¹⁴ )(1390)
ΔU = 4.6704 x 10⁻¹¹ J
The answer is 15.0N its explained in newtons third law hope this helps:)
Answer:
Option A: 600 kg.m/s westward
Explanation:
The scenario in question here implies a Linear (straight horizontal line) collision.
Usually, when there is a collision between two(2) objects moving opposite to each other like stated above, the object with the higher momentum tends to be more difficult to stop.
The Formula to use here is: P(w) + P(e) = P(total)
where P(w) is the momentum of the first vehicle travelling Westward,
P(e) is the momentum of the second vehicle travelling Eastward and
P(total) is the total amount of momentum after the collision.
Therefore,
1,800 kg.m/s + (-1,200 kg.m/s) = 600 kg.m/s in the westward direction (Our Answer)
Please note that the negative sign in front of (-1,200 kg.m/s) implies that it is moving in a direction opposite to that of the other vehicle.