Answer:
0.33 mol/kg NH₃
Explanation:
Data:
b(NH₃) = 0.33 mol/kg
b(Na₂SO₄) = 0.10 mol/ kg
Calculations:
The formula for the boiling point elevation ΔTb is
i is the van’t Hoff factor — the number of moles of particles you get from a solute.
(a) For NH₃,
The ammonia is a weak electrolyte, so it exists almost entirely as molecules in solution.
1 mol NH₃ ⟶ 1 mol particles
i ≈ 1, and ib = 1 × 0.33 = 0.33 mol particles per kilogram of water
(b) For Na₂SO₄,
Na₂SO₄(aq) ⟶ 2Na⁺(aq) + 2SO₄²⁻(aq)
1 mol Na₂SO₄ ⟶ 3 mol particles
i = 1 and ib = 3 × 0.10 = 0.30 mol particles per kilogram of water
The NH₃ has more moles of particles, so it has the higher boiling point.
Answer:
Carbon
Explanation:
The field of organic chemistry is the field of the study of the compounds of carbon mostly with hydrogen but they can contain the presence of other atoms such as oxygen, nitrogen, sulfur even metals such as lithium. It studies the structure, properties, synthesis and reactions of these compounds. The field of organic chemistry is the field of living organisms as they are mostly are formed by organic compounds hence its name organic.
Answer:
(a) when a reaction system reaches a state of equilibrium, the concentration of the products is equal to the concentration of the reactants
Answer:
Ammonia is an Arrhenius base and a Brønsted-Lowry base.
Explanation:
An Arrhenius base is any substance which, when it is dissolved in an aqueous solution, produces hydroxide (OH^-), ions in solution. An aqueous solution is a solution that has water present in it.
A Bronsted-Lowry base is a substance that accepts a proton, that is, a hydrogen ion (H^+).
Looking at the equation above, ammonia satisfies both characteristics. We can see that when ammonia is dissolved in water, hydroxide ions is produced in the solution. Hence it is an Arrhenius base. Similarly, the hydroxide ion is formed when ammonia accepts a proton. This is a characteristic of a Brownstead-Lowry base. Hence ammonia is both an Arrhenius base and a Brownstead-Lowry base.
Answer:
we use: V = pi*(r^2)*h
V = 3.14*(12.0cm^2)*44.0 cm
V = 19895.04 cm^3
Therefore, mass = (8.90g/cm^3) * (19895.04 cm^3) = 177065.856 g
Explanation:
