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Roman55 [17]
2 years ago
8

Given a force of 100 N and acceleration of 5 m/s2, what is the mass

Physics
1 answer:
tatyana61 [14]2 years ago
8 0

Answer:

20 kg

Explanation:

remember the equation f=ma.

100 N=force

5 m/s2= acceleration

so you need to divide force by acceleration: 100 N/ 5 m/s2= 20 kg, to get the mass.

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Grinding pepper is a physical change
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A small bug is lying resting when nine ants simultaneously ambush it and begin pulling it in different directions. They are each
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Answer: The bug will remain motionless

Explanation:

According to Newton's first Law of Motion (sometimes called Law of Inertia):

<em>An object at rest or describing a uniform straight line motion (moving at constant velocity), will remain at rest or moving unless an external force is applied to it and changes its state of rest or motion. </em>

In other words:

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This means that objects tend to remain in its state of motion, and is the definition of the inertia, as well.

In addition, according to his law, an object in rest can be in equilibrium (net force equals to zero), and a moving object can also be in equilibrium, as long as it keeps a constant velocity.

<h2>This is why the bug, which is at rest will remain at rest, although the ants are simultaneously pulling it in different directions, since the resultant of all these forces is zero.</h2>
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2 years ago
Earth's gravitational field is strongest at _______.
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The part of a vompressional wave that has the lowest density is the
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3 years ago
The first artificial satellite to orbit the Earth was Sputnik I, launched October 4, 1957. The mass of Sputnik I was 83.5 kg, an
9966 [12]

Answer:

-4.941*10^8J.

Explanation:

To solve this exercise it is necessary to take into account the concepts related to gravitational potential energy, as well as the concept of perigee and apogee of a celestial body.

By conservation of energy we know that,

\Delta U = \Delta_{perogee}-\Delta_{Apogee}

Where,

U= \frac{-GmM_e}{r}

Replacing

\Delta U = \frac{-GmM_e}{r_p}- \frac{-GmM_e}{r_a}

\Delta U = GmM_e (\frac{1}{r_A}-\frac{1}{r_p})

Our values are given by,

m = 85.5Kg

M_e = 5.97*10^{24}Kg

r_A = 7330Km

r_p = 6610Km

G = 6.67*10^{-11}Nm^2/Kg^2

Replacing at the equation,

\Delta U = (6.67*10^{-11})(85.5)(5.97*10^{24}) (\frac{1}{7330}-\frac{1}{6610})

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Therefore the Energy necessary for Sputnik I as it moved from apogee to perigee was -4.941*10^8J.

4 0
3 years ago
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