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2 years ago

Given a force of 100 N and acceleration of 5 m/s2, what is the mass

Physics

1 answer:

tatyana61 [14]2 years ago

8 0

Answer:

20 kg

Explanation:

remember the equation f=ma.

100 N=force

5 m/s2= acceleration

so you need to divide force by acceleration: 100 N/ 5 m/s2= 20 kg, to get the mass.

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Use the table below to calculate the acceleration of the object. Time (s) 0.0 3.0 6.0 9.0 Velocity (m/s) 0.0 1.2 2.4 3.6

antiseptic1488 [7]

explanation

a=average velocity/average time

average velocity=0.0+1.2+2.4+3.6/4

average velocity=7.2/4

average velocity=1.8 m/s

average time=0.0+3.0+6.0+9.0/4

average time=18/4

average time=4.5 s

a= average velocity/average time

a=1.8/4.5

a=0.4 m/s²

8 0

3 years ago

A very hard rubber ball (m = 0.5 kg) is falling vertically at 4 m/s just before it bounces on the floor. The ball rebounds back

saw5 [17]

Answer:

The force exerted by the floor is 80 N.

Explanation:

Given that,

Mass of ball = 0.5 kg

Velocity= 4 m/s

Time t = 0.05 s

When the ball rebounds then the kinetic energy is

$K.E =\dfrac{1}{2}mv^2$

Where, m = mass of ball

v = velocity of ball

Put the value into the formula

$K.E=\dfrac{1}{2}\times0.5\times(4)^2$

$K.E = 4\ J$

The average force exerted by the floor on the ball = change in kinetic energy over collision time

$F = \dfrac{4}{0.05}$

$F=80\ N$

Hence, The force exerted by the floor is 80 N.

4 0

2 years ago

A solid metal object hangs from a force sensor by a thread in the open air, and the actual weight is measured to be 0.71 N. Then

Alexeev081 [22]

Answer:

The apparent weight of the object is 0.465 N.

Explanation:

Given that,

Weight = 0.71 N

Water level = 50 mL

object inserted = 75 mL

We need to calculate the volume of solid

Using formula of volume

$V=25\ ml = 25\times10^{-6}\ m^3$

We need to calculate the buoyancy force

Using formula of buoyancy force

$F'= V\rho g$

Put the value into the formula

$F'=25\times10^{-6}\times1000\times9.8$

$F'=0.245\ N$

We need to calculate the apparent weight of the object

Using formula of apparent weight

$W=F-F'$

Put the value into the formula

$W=0.71-0.245$

$W=0.465\ N$

Hence, The apparent weight of the object is 0.465 N.

5 0

2 years ago

What is the force weight of a jaguar who jumps 3 meters to a tree branch with 2670 J of work?

fgiga [73]

Answer:

$we \: know \: energy \: = \: force \: \times distance \\ e = f \times d \\ so \: f \: = \frac{e}{d} \\ so \: th \: force \: here \: = (\frac{2670}{3}) newton \\ = 890newton$

Hope it helps

7 0

3 years ago

A driver fills an 18.9L steel gasoline can with gasoline at 15.0°C right up to the top. He forgets to replace the cap and leaves

GarryVolchara [31]

Answer:

ΔV = 0.98 L

Explanation:

First, we will calculate the increased volume using Charles' Law:

$\frac{V_1}{T_1} = \frac{V_2}{T_2}$

where,

V₁ =initial volume = 18.9 L

V₂ = final volume = ?

T₁ = initial temperature = 15°C + 273 = 288 k

T₂ = final temperature = 30°C + 273 = 303 k

Therefore,

$\frac{18.9\ L}{288\ k} = \frac{V_2}{303\ k}$

V₂ = 19.88 L

Now, we calculate the change in volume:

ΔV = V₂ - V₁ = 19.88L - 18.9 L

This is the volume of gasoline that will spill out.

5 0

2 years ago