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3 years ago

After a car is jump started, you must unclip the jumper cable clips______.

Engineering

1 answer:

drek231 [11]3 years ago

8 0

Answer:

The correct answer is;

In the reverse order you connected them

Explanation:

The process of jump starting a car is as follows;

1) Connect the positive or red clip to the dead battery

2) Connect the other end of the positive or red clip to the other end of the live battery in the donor car

3) Connect the negative or black clip to the negative terminal on the live battery

4) Connect the other end of the negative or black clip to the bare metal (without paint coating) on the donor car

5) Start and idle the donor car

6) Test to see if there is electric power in the dead car. If yes, then start the dead car

By disconnecting in the reverse other, that is by first removing the black or negative terminal from the dead vehicle chassis, prevents short circuiting the system with the rest of the metals parts in vehicle body when a metal makes contact while the positive terminal is removed and the negative terminal is still on the chassis.

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One employee was climbing a metal ladder to hand an electric drill to the journeyman installer on a scaffold about five feet abo

lbvjy [14]

Answer:

ACCIDENT PREVENTION RECOMMENDATIONS

Fatal Fact made us to understand some of the prevention techniques as stated below.

1. Use approved ground fault circuit interrupters or an assured equipment grounding conductor program to protect employees on construction sites.

2. Use equipment that provides a permanent and continuous path from circuits, equipment, structures, conduit or enclosures to ground.

3. Inspect electrical tools and equipment daily and remove damaged or defective equipment from use until it is repaired.

Explanation:

In order to gain a better understanding of the answer above let explain some terms

Ground Fault Circuit Interrupters :

A ground fault circuit interrupter (GFCI), or Residual Current Device (RCD) is a type of circuit breaker which shuts off electric power when it senses an imbalance between the outgoing and incoming current. The main purpose is to protect people from an electric shock caused when some of the current travels through a person's body due to an electrical fault such as a short circuit, insulation failure, or equipment malfunction.

So the first statement is implying that in order to prevent this accident that this device (GFCI) should have been used in that construction site, or as an alternative before the construction commenced the company should have drafted a lay down conductor program(i.e. a step by step conductor program) that assured equipment grounding in order to protect employees on construction sites

5 0

3 years ago

What have you learned about designing solutions? How does this apply to engineering? Think of some engineering solutions that st

Andrew [12]

Answer:

In engineering design, failure is expected. It helps you find the best solutions before implementing them in the “real world”. Having a prototype fail is a GOOD thing, because that means you have learned something new about the problem and potential solutions.

Explanation:

4 0

3 years ago

The water of a 14’ × 48’ metal frame pool can drain from the pool through an opening at the side of the pool. The opening is abo

Tresset [83]

Answer:

Explanation:

Height h = 1.03m

Volume v = 3780 gallons = 3780 * 0.0037851m^3 = 14.3073m^3

Time t = 13.5 mins = 13.5 * 60 = 810 seconds

Length of pool L = 14 inch = 14 * 2.54 = 35.56cm

width of pool b = 48 inch = 48 * 2.54 = 121.92 cm

a.) Consider the bernoulli's equation is given as:

$P_1+\rho gh_1 + \frac{1}{2}\rho v_1^2 = P_2 + \rho gh_2 + \frac{1}{2}\rho v_2^2 ...(1)$

consider the equation of bernoulli at the top of the pool

$P_0+\rho gh_1 + \frac{1}{2}\rho v_1^2 =constant ...(2)$

where $P_1=P_0$ atm pressure

At the top of the pool $v_1=0m/s$ , substitute in V_1 in equation (2)

$P_0+\rho gh_1 =constant ...(3)$

Hence equation (3) serves as the bernoullis equation at the top.

b.) Consider the equation of bernoulli's at the opening of the pool

$P_2+\rho gh_2 + \frac{1}{2}\rho v_2^2 =constant ...(4)\\P_0+\rho gh_2 + \frac{1}{2}\rho v_2^2 =constant ...(5)$

where $P_2=P_0$ atm pressure and $h_2=0m$

$P_0+\rho v_1^2 =constant ...(6)$

Hence equation (6) serves as the bernoullis equation of water at the opening of the pool.

c.) Consider the equation (3) and (4)

$P_0+\rho gh_1 =P_0+\rho v_1^2\\\\\frac{1}{2}\rho v_2^2=\rho gh_1\\v_2^2=2gh_1\\v_2=(\sqrt{2gh_1})m/s...(7)$

Hence velocity is $v_2=(\sqrt{2gh_1})m/s$

d.) consider (7)

$v_2=(\sqrt{2(9.81)(1.03)})=4.4954m/s(approx)$

This is the norminal value of velocity

e.) consider the equation of flow rate interval of v and t

flow(t)= $\frac{dv}{dt}(m^3/s)$ hence this is the flow rate

f.) Consider the equation cross sectional area in terms of V,v2 and t

$AV_2=\frac{v}{t}\\\\A=\frac{v}{v_2t}(m^2)...8$

hence this serves as the cross sectional area.

g.) Consider the equation of area from equation (8)

$A=\frac{v}{v_2t}\\=\frac{14.3073}{4.4954\times 810}=0.003929=0.00393m^2=39.3cm^2$

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3 years ago

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3 years ago

How would you expect an increase in the austenite grain size to affect the hardenability of a steel alloy? Why?

seraphim [82]

Answer:

The hardenability increases with increasing austenite grain size, because the grain boundary area is decreasing. This means that the sites for the nucleation of ferrite and pearlite are being reduced in number, with the result that these transformations are slowed down, and the hardenability is therefore increased.

3 0

3 years ago