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3 years ago

The truck now weighs 147,000 N what is the new mass of the truck

Physics

1 answer:

katrin [286]3 years ago

6 0

Answer:

14700kg

Explanation:

If you divide it by 10

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A flowerpot falls from the ledge of an apartment building. A person in an apartment below, coincidentally holding a stopwatch, n

valkas [14]

Answer

given,

height of window = 4 m

time taken to travel = 1 s

acceleration due to gravity = 9.8 m/s²

$s = ut + \dfrac{1}{2}at^2$

$u = \dfrac{s - \dfrac{1}{2}at^2}{t}$

$u = \dfrac{4 - \dfrac{1}{2}\times 9.8\times 1^2}{1}$

u = -0.905 m/s

initial velocity of ledge v = 0

now,

v² = u² + 2 a s

(-0.905)² = 0 + 2 × 9.8 ×s

s = 0.042 m

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3 years ago

As a substance melts, heat energy is used to break the connections between molecules, and temperature __________ until all melti

mario62 [17]

Temperature stays the same

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3 years ago

Light is emitted by electrons when they drop from one energy level to a lower level. Which transition results in the emission of

natulia [17]

Answer:

Level 4 to level 2

Explanation:

Electrons in an atom are contained in specific energy levels (1, 2, 3, and so on) having different distances from the nucleus. When light is emitted by electrons from one energy level to a lower level, level 4 to level 2 has the greatest energy.

Hence, the correct option is "Level 4 to level 2".

3 0

3 years ago

Starting from rest, a person runs with a constant acceleration, traveling 40 meters in 10 seconds. What is their final velocity?

Assoli18 [71]

Answer:

Final velocity v = 8.944 m/sec

Explanation:

We have given distance S = 40 meters

Time t = 10 sec

As it starts from rest so initial velocity u = 0

From second equation of motion $s=ut+\frac{1}{2}at^2$

$40=0\times 10+\frac{1}{2}a10^2$

$a=0.8944m/sec^2$

Now from first equation of motion $v=u+at$ , here v is final velocity, u is initial velocity, a is acceleration and t is time

So $v=u+at=0+0.8944\times 10=8.944m/sec$

6 0

3 years ago

A uniform linear charge of 2.0 nC/m is distributed along the x axis from x = 0 to x = 3 m. What is the x component of the electr

balu736 [363]

Answer:

The x component of the electric field at y=2m is $E_{x}=17.97\frac{N}{C}$

Explanation:

For a linear charge, using Gauss Law, we get that the Electric field (radial) has the following form

$E=\frac{\lambda}{2\pi\epsilon_{0}r}$

where λ is the charge for longitud unit given in the problem, r is replaced by the y coordinate, and there are two known more data. So

$E=\frac{2*10x^{-9}}{2*2\pi\epsilon_{0}}=17.97\frac{N}{C}$

is the x component of the Electric field at y=2m on the y axis, which is what we wanted to know.

4 0

3 years ago