Answer:
Force in the rocket will be 4166.64 N
Explanation:
We have given mass of the rocket m = 3 kg
Rocket acquires a speed of 50 m sec so final speed v = 50 m/sec
Initial speed u = 0 m/sec
Distance traveled s = 90 cm = 0.9 m
From third equation of motion we know that
From newton's law we F = ma
So force will be
So force in the rocket will be 4166.64 N
Answer:
40 m/s
Explanation:
If you multiply the acceleration with time you get the average speed.
Answer:
The function that describe the motion in the time
y (t) = 0.28m * sin ( 36.025 * t)
Explanation:
The angular frequency of oscillation of the spring
w = √k/m
w = √305 N/m / 0.235 kg
w = 36.025 rad / s
To determine the function of the motion knowing as a motion oscillation in a amplitude a frequency
y(t) = A * sin (w t )
So
A = 28.0 cm * 1 m / 100 cm = 0.28 m
So replacing to determine the function of the motion in the time
y (t) = A sin (w t)
y (t) = 0.28m * sin ( 36.025 * t)