Answer:
83,900 J
Explanation:
First, find the acceleration:
F = ma
1150 N = (1600 kg) a
a = 0.719 m/s²
Now find the final velocity.
Given:
Δx = 45.8 m
v₀ = 6.25 m/s
a = 0.719 m/s²
Find: v
v² = v₀² + 2aΔx
v² = (6.25 m/s)² + 2 (0.719 m/s²) (45.8 m)
v = 10.2 m/s
Now find the final KE:
KE = ½ mv²
KE = ½ (1600 kg) (10.2 m/s)²
KE = 83,920 J
Rounded to three significant figures, the final kinetic energy is 83,900 J.
Take your time, do not get distracted , do not talk and focus on the exam
Answer:
u can use a calculator to answer that question thats ur only hint
Explanation:
Answer:
The heat flow through the slab in a day is 432,000 J
Explanation:
Q = kA∆T/t
Q is rate of heat flow
k is thermal conductivity = 0.1 J/s/m.°C
A is area = 100 cm^2 = 100 cm^2 × (1 m/100 cm)^2 = 0.01 m^2
∆T is temperature difference = 100 °C
t is thickness = 2 cm = 2/100 = 0.02 m
Q = 0.1×0.01×100/0.02 = 5 J/s
In a day, there are 24×60×60 = 86,400 s
Heat flow in a day = 5 J/s × 86,400 s = 432,000 J
