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MrRa [10]
3 years ago
12

Intro/forces honors physics please help asap

Physics
1 answer:
kaheart [24]3 years ago
5 0

Answer:

I think it should be D

Explanation:

This is because the arrow pointing right is bigger than the arrow pointing left. Hence we can conclude the the force acting on the right is greater and hence it is accelerating

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A tunnel has a length of 50 km. A car takes 20 min to travel between the two ends of the tunnel. What is the average speed of th
Luda [366]

Answer:

150 km/h

Explanation:

50km/20min = x km/60 min

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How do forces affect a body's motion?
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By putting to much weight on it our body causing it to hurt or fall hope this helps
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A train car has a mass of 10,000 kg and is moving at +3.0 m/s. It strikes an identical train car that is at rest. The train cars
shtirl [24]
In order to compute the final velocity of the trains, we may apply the principle of conservation of momentum which is:
initial momentum = final momentum
m₁v₁ = m₂v₂

The final mass of the trains will be:
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3 0
3 years ago
Having landed on a newly discovered planet, an astronaut sets up a simple pendulum of length 1.38 m and finds that it makes 441
Tasya [4]
The period of a simple pendulum is given by:
T=2 \pi  \sqrt{ \frac{L}{g} }
where L is the pendulum length, and g is the gravitational acceleration of the planet. Re-arranging the formula, we get:
g= \frac{4 \pi^2}{T^2}L (1)

We already know the length of the pendulum, L=1.38 m, however we need to find its period of oscillation.

We know it makes N=441 oscillations in t=1090 s, therefore its frequency is
f= \frac{N}{t}= \frac{441}{1090 s}=0.40 Hz
And its period is the reciprocal of its frequency:
T= \frac{1}{f}= \frac{1}{0.40 Hz}=2.47 s

So now we can use eq.(1) to find the gravitational acceleration of the planet:
g= \frac{4 \pi^2}{T^2}L =  \frac{4 \pi^2}{(2.47 s)^2} (1.38 m) =8.92 m/s^2
3 0
3 years ago
Which of the following is NOT usually published with a scientific report?
dusya [7]

C cost (I need points)

5 0
3 years ago
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