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abruzzese [7]
3 years ago
14

Hii please help i’ll give brainliest!!

Physics
2 answers:
ASHA 777 [7]3 years ago
8 0

Answer: The answer to it is

B

Explanation:

d1i1m1o1n [39]3 years ago
4 0

Answer: It is the second one

Explanation: Just please trust me on this one

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Help!! this makes no sense to me
bulgar [2K]
3 meters i’m pretty sure
8 0
2 years ago
Read 2 more answers
A bungee jumper with a weight of 613 N leaps off
Ierofanga [76]

Answer:

13.9 kJ

Explanation:

Work = force × distance

W = (613 N) (22.6 m)

W = 13,900 J

W = 13.9 kJ

6 0
4 years ago
A car is moving with speed 20 m/s and acceleration 2 m/s2 at a given instant. Using a second-degree Taylor polynomial, estimate
PilotLPTM [1.2K]

Answer:

T(1)=21

Explanation:

The equation of the position in kinematics is given:

x(t)=x_{0}+v_{0}t+0.5at^{2}

  • x(0) is the initial position, in this it is 0
  • v(0) is the initial velocity (20 m/s)
  • a is the acceleration (2 m/s²)

So the equation will be:

x(t)=20t+0.5*2*t^{2}

x(t)=20t+t^{2}    

Now, the Taylor polynomial equation is:

f(a)+\frac{f'(a)}{1!}(x-a)+\frac{f''(a)}{2!}(x-a)^{2}+...

Using our position equation we can find f'(t)=v(t) and f''(x)=a(t). In our case a=0, so let's find each derivative.

f(t)=x(t)=20t+t^{2}

f'(t)=\frac{dx(t)}{dt}=v(t)=20+2t

f''(t)=\frac{dv(t)}{dt}=a(t)=2

Using the Taylor polynomial with a = 0 and take just the second order of the derivative.

f(0)+\frac{f'(0)}{1!}(x)+\frac{f''(0)}{2!}(x)^{2}

f(0)=x(0)=0

f'(0)=v(0)=20

f''(0)=a(0)=2

T(t)=f(0)+\frac{f'(0)}{1!}(t)+\frac{f''(0)}{2!}(t)^{2}

T(t)=\frac{20}{1!}(t)+\frac{2}{2!}(t)^{2}

T(t)=20t+t^{2}

Let's put t=1 so find the how far the car moves in the next second:

T(1)=20*1+1^{2}

T(1)=21

Therefore, the position in the next second is 21 m.

We need to know if the acceleration remains at this value to use this polynomial in the next minute, so I suggest that it would be reasonable to use this method just under this condition.

I hope it helps you!

4 0
3 years ago
How many kilometers are in 1.40 miles​
ELEN [110]
The answer is 2.25308 km
4 0
3 years ago
A friend of yours is loudly singing a single note at 412 Hz while racing toward you at 25.8 m/s on a day when the speed of sound
xeze [42]

Answer:

5541Hz

Explanation:

If the frequency of a wave is directly proportional to the velocity we have;

F = kV where;

F is the frequency

K is the constant of proportionality

V is the velocity

Since f = kV

K = f/v

K = F1/V1 = F2/V2

Given f1 = 412Hz v1 = 25.8m/s f2 = ? V2 = 347m/s

Substituting in the formula we have;

412/25.8=f2/347

Cross multiplying

25.8f2 = 412×347

F2 = 412×347/25.8

F2 = 5541Hz

The frequency heard will be 5541Hz

6 0
3 years ago
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