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german
3 years ago
14

What volume (in L) of a 6.84 M.

Chemistry
1 answer:
grandymaker [24]3 years ago
4 0

Answer:

0.158L

Explanation:

From the question, we obtained the following information:

C1 = 6.84 M

V1 =?

C2 = 1.84 M

V2 = 588 mL = 588/1000 = 0.588L

Using the dilution formula C1V1 = C2V2. The original volume can calculated for as follows:

C1V1 = C2V2

6.84 x V1 = 1.84 x 0.588

Divide both side by 6.84

V1 =(1.84 x 0.588) / 6.84

V1 = 0.158L

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11.412 x 10^23.

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<em />

To solve this question we need to determine the moles of ethene in 50.4kg. 1/3 these moles are the moles of C₂₁H₄₄ that must be added:

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<h3>177.3kg C₂₁H₄₄</h3>
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