Which element requires the least amount of
energy to remove the most loosely held electron
from a gaseous atom in the ground state?
<h3>Answer-</h3><h3>Na</h3>
The half-life equation is written as:
An = Aoe^-kt
We use this equation for the solution. We do as follows:
5.5 = 176e^-k(165)
k = 0.02
<span>What is the half-life of the goo in minutes?
</span>
0.5 = e^-0.02t
t = 34.66 minutes <----HALF-LIFE
Find a formula for G(t) , the amount of goo remaining at time t.G(t)=?
G(t) = 176e^-0.02t
How many grams of goo will remain after 50 minutes?
G(t) = 176e^-0.02(50) = 64.75 g
Answer:
6 carbon atoms
Explanation:
For instance, we can say that one molecule of glucose has 6 carbon atoms, or we can say, equivalently, that one mole of glucose has 6 moles of carbon atoms
Gas I think if I’m wrong it’s solid and if that’s wrong it’s liquid please give me brainliest
<span>S + O2 = SO2
1 mole S ------------- 1 mole SO2
( moles S ) --------- 15.0 moles SO2
moles S = 15.0 x 1 / 1
moles S = 15.0 / 1
= 15.0 moles S</span>
