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natita [175]
2 years ago
6

A β− and a β+ particle meet and interact within a tissue. Discuss what would be the likely outcome of this interaction.

Physics
1 answer:
Arturiano [62]2 years ago
3 0

When a β− and a β+ particle meet and interact they are annihilated.

Every matter has an antimatter. An antimatter of a particular particle is another particle that has exactly the same properties as the initial particle but carries an opposite charge.

If we look at β− and β+ particles, we will notice that they are matter and antimatter. The interaction of matter and antimatter leads to annihilation. The energy produced by annihilation of matter and antimatter is enough to destroy the tissue.

So, when β− and a β+ particle meet and interact they are annihilated.

Learn more: brainly.com/question/23266051

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Determine the magnitude of the resultant force acting on a 1.5 −kg particle at the instant t=2 s, if the particle is moving alon
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Answer:

F = 63N

Explanation:

M= 1.5kg , t= 2s, r = (2t + 10)m and

Θ = (1.5t² - 6t).

magnitude of the resultant force acting on 1.5kg = ?

Force acting on the mass =

∑Fr =MAr

Fr = m(∇r² - rθ²) ..........equation (i)

∑Fθ = MAθ = M(d²θ/dr + 2dθ/dr) ......... equation (ii)

The horizontal path is defined as

r = (2t + 10)

dr/dt = 2, d²r/dt² = 0

Angle Θ is defined by

θ = (1.5t² - 6t)

dθ/dt = 3t, d²θ/dt² = 3

at t = 2

r = (2t + 10) = (2*(2) +10) = 14

but dr/dt = 2m/s and d²r/dt² = 0m/s

θ = (1.5(2)² - 6(2) ) = -6rads

dθ/dt =3(2) - 6 = 0rads

d²θ/dt = 3rad/s²

substituting equation i into equation ii,

Fr = M(d²r/dt² + rdθ/dt) = 1.5 (0-0)

∑F = m[rd²θ/dt² + 2dr/dt * dθ/dt]

∑F = 1.5(14*3+0) = 63N

F = √(Fr² +FΘ²) = √(0² + 63²) = 63N

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3 years ago
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The correct answer is

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