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Ludmilka [50]
3 years ago
5

URGENT!!!

Physics
1 answer:
Rama09 [41]3 years ago
6 0

The amount of NOx emission produced by a household is required.

The total amount of NOx the household is responsible for is 91.06 kg.

1 car produces 11 kg of NOx per year.

Natural gas burning produces 4.3 g of NOx per therm.

Electric power plant produces 7.1 g of NOx per kwh.

2 cars will produce 2\times 11=22\ \text{kg} of NOx.

1200 therms of natural gas will produce 1200\times 4.3=5160\ \text{g}

9000 kWh will produce 7.1\times 9000=63900\ \text{g}

Converting all to kg and finding the total amount

22+5.16+63.9=91.06\ \text{kg}

The total amount of NOx the household is responsible for is 91.06 kg.

Learn more:

brainly.com/question/23262386

brainly.com/question/12707452

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What is the mass of metal if it has a density of 12.459 hg/cm^3 and displaces 28.7cm^3 of water ​
natima [27]

Answer:

357.6g

Explanation:

Given parameters:

Density  = 12.459g/cm³

Volume of metal  = 28.7cm³

Unknown:

Mass of metal = ?

Solution:

The density of a substance is its mass per unit volume.

To find the mass;

     Mass of metal  = density x volume

Now insert the parameters and solve;

    Mass of metal  = 12.459 x 28.7  = 357.6g

7 0
3 years ago
Covert 35000000 miles to meters and show how you got the answer?
Lina20 [59]

Answer:

56327040000 metres

Explanation:

1 mile =

1609.344 metres

35000000 miles = x meters

we represent x by the number of meters which the requested miles maps to

we cross multiply, so 1609.344×35000000 = 1 × x

x =56327040000 metres

8 0
3 years ago
The viewing screen in a double-slit experiment with monochromatic light. Fringe C is the central maximum. The fringe separation
makvit [3.9K]

Answer:

<em>Part A</em><em>:</em>

a) If the wavelength of the light is decreased the fringe spacing Δy will decrease.

<em>Part B</em><em>:</em>

b) If the spacing between the slits is decreased the fringe spacing Δy will increase.

<em>Part C</em><em>:</em>

a) If the distance to the screen is decreased the fringe spacing will decrease.

<em>Part D</em><em>:</em>

The dot in the center of fringe E is 920\ x\ 10^{-9} m farther from the left slit than from the right slit.

Explanation:

In the double-slit experiment there is a clear contrast between the dark and bright fringes, that indicate destructive and constructive interference respectively, in the central peak and then is less so at either side.

The position of bright fringes in the screen where the pattern is formed can be calculated with

                      \vartriangle y =\frac{m \lambda L}{d}

                      m=0,\pm 1,\pm 2,\pm 3,.....

  1. m is the order number.
  2. \lambda is the wavelength of the monochromatic light.
  3. L is the distance between the screen and the two slits.
  4. d is the distance between the slits.
  • Part A:  a) In the above equation for the position of bright fringes we can see that if the wavelength of the light \lambda is decreased the overall effect will be that the fringes are going to be closer. That means that the fringe spacing Δy will decrease.
  • Part B:  b) In the above equation for the position of bright fringes we can see that if the spacing between the slits d is decreased the fringes are going to be wider apart. That means the fringe spacing Δy will increase.
  • Part C:  a) In the above equation we can see that if the distance to the screen L is decreased the fringes are going to be closer. That means the fringe spacing Δy will decrease.
  • Part D: We are told that the central maximum is the fringe C that corresponds with m=0. That means that fringe E corresponds with the order number m=2 if we consider it to be the second maximum at the rigth of the central one. To calculate how much farther from the left slit than from the right slit is a dot located at  the center of the fringe E in the screen we use the condition for constructive interference. That says that the  path length difference Δr between rays coming from the left and right slit must be \vartriangle r=m \lambda

        We simply replace the values in that equation :

                      \vartriangle r= m \lambda =2.\ 460\ nm

                      \vartriangle r= 920\ x\ 10^{-9} m

         The dot in the center of fringe E is 920\ x\ 10^{-9}m farther from the left slit than from the right slit.

     

       

       

     

3 0
3 years ago
To make a given sound seem twice as loud, how should a musician change the intensity of the sound?
Serhud [2]

Answer:

C. Quadruple the intensity

Explanation:

The intensity of the sound is proportional to square of amplitude of the sound.

I ∝ A²

\frac{I_1}{A_1^2} = \frac{I_2}{A_2^2}\\\\I_2 = \frac{I_1A_2^2}{A_1^2}

When the given sound is twice loud as the initial value, then the new amplitude is twice the former.

A₂ = 2A₁

I_2 = \frac{I_1A_2^2}{A_1^2} \\\\I_2 = \frac{I_1(2A_1)^2}{A_1^2} \\\\I_2 = \frac{4I_1A_1^2}{A_1^2}\\\\ I_2 = 4I_1

Thus, to make a given sound seem twice as loud, the musician should Quadruple the intensity

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3 years ago
Which pair does NOT have an electric force between them?.
viva [34]

Two neutral objects will not have any electric force of attraction or repulsion between them.

<h3>What is the condition for the electric force between two objects?</h3>

As we know from the electrostatics that whenever there are two charges having a positive charge on one and a negative on the other will attract each other

similarly, if they are having like charges which are both of them having positive or both of them having a negative charge then there will be a force of repulsion between them.

But if both of them or even one of them is neutral then there will not be any electric force between them.

Thus neutral objects will not have any electric force of attraction or repulsion between them.

To know more about the nature of charged particles follow

brainly.com/question/22492496

5 0
2 years ago
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