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Montano1993 [528]

3 years ago

7

The aircraft link is made from an a992 steel rod. determine the smallest diameter of the rod, to the nearest 1 /16 in., that wil

l support the load of 4 kip without buckling. the ends are pin connected.

1 answer:

Bas_tet [7]3 years ago

3 0

Answer:

hjhjhjhj

Explanation:

jhjhjhjhjh

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When are magnets attracted and when are they repelled.

vova2212 [387]

Magnets are attracted when each of the different sides, most commonly known as "North" and "South", are facing each other. They repel when North and North, or South and South are facing each other.

3 0

3 years ago

A light has wavelength of is used in the double slits experiment . Which of the following values represent the phase difference

Wewaii [24]

Answer:

s

Explanation:

8 0

3 years ago

A 103 kg physics professor has fallen into the Grand Canyon. Luckily, he managed to grab a branch and is now hanging 93 m below

siniylev [52]

Answer:

125.83672 seconds

Explanation:

P = Power of the horse = 1 hp = 746 W (as it is not given we have assumed the horse has the power of 1 hp)

m = Mass of professor = 103 kg

g = Acceleration due to gravity = 9.8 m/s²

h = Height of professor = 93 m

Work done would be equal to the potential energy

$W=mgh\\\Rightarrow W=103\times 9.8\times 93\\\Rightarrow W=93874.2\ J$

Power is given by

$P=\frac{W}{t}\\\Rightarrow t=\frac{W}{P}\\\Rightarrow t=\frac{93874.2}{746}\\\Rightarrow t=125.83672\ seconds$

The time taken by the horse to pull the professor is 125.83672 seconds

6 0

3 years ago

How do birds manage to fly without flapping their wings?

nignag [31]

It's called gliding.
So, they will get up high and collect their balance and be nice and steady. Then, they can spread their wings out and glide. The wind will carry them from their.
How do we manage to stand without constantly walking? It's the same exact thing.

3 0

3 years ago

The flash unit in a camera uses a special circuit to "step up" the 3.0 V from the batteries to 360 V , which charges a capacitor

aksik [14]

Answer:

The capacitance of the capacitor is $1.85*10^{-5}F$

Explanation:

To solve this exercise it is necessary to apply the concepts related to Power and energy stored in a capacitor.

By definition we know that power is represented as

$P = \frac{E}{t}$

Where,

E= Energy

t = time

Solving to find the Energy we have,

$E = P*t$

Our values are:

$P = 1*10^5W$

$t = 12*10^{-6}s$

Then,

$E= (1*10^5)(12*10^{-6})$

$E = 1.2J$

With the energy found we can know calculate the Capacitance in a capacitor through the energy for capacitor equation, that is

$E=\frac{1}{2}CV^2$

Solving for C=

$C = \frac{1}{2}\frac{E}{V^2}$

$C = 2\frac{1.2}{(360^2-3^2)}$

$C = 1.85*10^{-5}F$

Therefore the capacitance of the capacitor is $1.85*10^{-5}F$

7 0

3 years ago