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Nonamiya [84]
3 years ago
8

Which is not an example of a compound? O3 H2O2 NCl3 KOH

Chemistry
2 answers:
Alenkinab [10]3 years ago
5 0

Answer:

the answer is 03.

Explanation:

m_a_m_a [10]3 years ago
3 0

Answer:

03

Explanation:

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Why is a very small amount of cerium oxide nanoparticles need: A) the nanoparticles are elements
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A. Fluorine typically gains 1 electron, like the rest of the halogens.
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How many moles of NaCl are present in a solution with a molarity of 8.59 M and a volume of 125 mL
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a 5L container contains 3 moles of helium and 4 moles of hydrogen at a pressure of 9 atms maintaining a constant T and additiona
Stells [14]

Answer:

7.71 atm

Explanation:

Given the following data:

V = 5 L

n_{He} = 3 mol

n_{H_2} = 4 mol

p_1 = 9 atm

T = const

According to the ideal gas law, we know that the product between pressure and volume of a gas is equal to the product between moles, the ideal gas law constant and the absolute temperature:

pV = nRT

Since the temperature and the ideal gas constant are constants, as well as the fixed container volume of 5 L, we may rearrange the equation as:

\frac{p}{n}=\frac{RT}{V}=const

This means for two conditions, we'd obtain:

\frac{p_1}{n_1}=\frac{p_2}{n_2}

Given:

p_1 = 9 atm

n_1 = n_{initial total} = n_{He} + n_{H_2} = 3 mol + 4 mol = 7 mol

n_2 = n_{final total} = n_{He} + n_{H_2} = 3 mol + 4 mol + 2 mol = 9 mol

Solve for the final pressure:

p_2 = p_1\cdot \frac{n_2}{n_1}

Now, according to the Dalton's law of partial pressures, the partial pressure is equal to the total pressure multiplied by the mole fraction of a component:

p_{H_2}=\chi_{H_2}p_2

Knowing that:

p_2 = p_1\cdot \frac{n_2}{n_1}

And:

\chi_{H_2}=\frac{n_H_2}{n_2}

The equation becomes:

p_{H_2}=\chi_{H_2}p_2=p_1\cdot \frac{n_2}{n_1}\cdot \frac{n_H_2}{n_2}=p_1\cdot \frac{n_H_2}{n_1}

Substituting the variables:

p_{H_2}=9 atm\cdot \frac{4 mol + 2 mol}{7 mol}=7.71 atm

6 0
2 years ago
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