3 years ago

Could someone answer this please?

Physics

2 answers:

Harman [31]3 years ago

8 0

Answer: The answer is B!

Explanation:

Elina [12.6K]3 years ago

7 0

Answer: C is the correct answer

Explanation:

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Two loudspeakers are placed on a wall 3.00 m apart. A listener stands 3.00 m from the wall directly in front of one of the speak

Mashutka [201]

Answer:

Part a)

$\Delta \phi = 2.2 \pi$

Part b)

$f = 411.3 Hz$

Explanation:

As we know that the observer is standing in front of one speaker

So here the path difference of the two sound waves reaching to the observer is given as

$\Delta x = 3\sqrt2 - 3$

$\Delta x = 1.24 m$

now phase difference is related with path difference as

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$\Delta \phi = \frac{2\pi}{\lambda}(1.24)$

here in order to find the wavelength

$\lambda = \frac{c}{f}$

$\lambda = \frac{340}{300} = 1.13$

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Part b)

Now we know that when phase difference is odd multiple of $\pi$

then in that case the the sound must be minimum

So nearest value for minimum intensity would be

$\Delta \phi = 3\pi$

so we have

$3\pi = \frac{2\pi}{\lambda}(1.24)$

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$\lambda = 0.827$

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