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OLEGan [10]
2 years ago
7

Could someone answer this please?

Physics
2 answers:
Harman [31]2 years ago
8 0

Answer: The answer is B!

Explanation:

Elina [12.6K]2 years ago
7 0

Answer: C is the correct answer

Explanation:

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Answer:

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Explanation:

Given:

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Part a

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Part b

vf = vi + a*t\\vf^2 = vi^2 + 2*a*s\\\\0 = 22 + a*t\\t = -22 /a\\\\0 = 484 +2*a*(0.62)\\a = - 390.3232 m/s^2\\\\t = -22/(-390.3232)\\\\t = 0.0564 s

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Explanation:

The energy used to draw the bowstring = the kinetic energy of the arrow.

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make v the subject of the equation

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Given: F = 201 N, m = 0.3 kg, d = 1.3 m.

Substitute into equation 2

v = √(2×201×1.3/0.3)

v = √(1742)

v = 41.74 m/s.

Hence the arrow leave the bow with a speed of 41.74 m/s

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3 years ago
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