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icang [17]
4 years ago
12

Dilutions Worksheet - Solutions

Chemistry
1 answer:
xxMikexx [17]4 years ago
3 0

Answer:

\large \boxed{\text{0.64 mol/L}}

Explanation:

The original solution was diluted from 250 mL to 295 mL

We can use the dilution formula to calculate the concentration of the diluted solution.

\begin{array}{rcl}V_{1}c_{1} & = & V_{2}c_{2}\\\text{250 mL }\times \text{0.75 mol/L} & = & \text{295 mL} \times c_{2}\\c_{2}& = & \dfrac{250}{295}\times \text{0.75 mol/L}\\\\& = &  \text{0.64 mol/L}\\\end{array}\\\text{The molar concentration of the diluted solution is $\large \boxed{\textbf{0.64 mol/L}}$}

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8 0
3 years ago
It was found that 2.35 g of a compound of phosphorus and chlorine contained 0.539 g of phosphorus. What are the percentages by m
igor_vitrenko [27]

Answer:

Explanation:

P = 2.35g

Cl= 0.539 g

% MASS = mass of  X/ mass of a compound

 % mass of P =   2.35 / (2.35+ 0.539) =  81.34%

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3 0
4 years ago
In one compound of lead and sulfur, there are 6.46 g of lead
timurjin [86]

Answer:

Lead to Sulfur = 2 : 1

Explanation:

Given

Represent lead with L and Sulfur with S

L1 = 6.46g for S1 = 1 g

L2= 3.23g for S2 = 1 g

Required

Determine the simple whole number ratio of L to S

Divide L1 by L2

L = L1/L2

L = 6.46g/3.23g

L = 2

Divide S1 by S2

S = 1g/1g

S = 1

Represent L and S as a ratio:

L : S = 2 : 1

Hence, the required ratio of Lead to Sulfur is 2 to 1

4 0
3 years ago
Summarize the five points of Dalton’s atomic theory, and explain at least one change that occurred to the atomic theory because
Umnica [9.8K]
The postulates of Dalton's theory were:
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2) <span>Atoms of a given element are identical in size, mass, and other properties
</span>3) <span>Atoms cannot be subdivided, created, or destroyed</span>
4) Atoms combine in whole number ratio to form compounds
5) Chemical reactions are the rearrangement of atoms
The third postulate has been disproved by modern science, in which the atom has been split and been subdivided into smaller parts such as the neutron, proton and electron, which are further subdivided into quarks, gluons, and kaons.
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4 0
3 years ago
Read 2 more answers
If 1.00 mol of argon is placed in a 0.500- L container at 24.0 ∘C , what is the difference between the ideal pressure (as predic
swat32

The difference between the ideal pressure and the pressure calculated by the Van Der Waal equation is 2.08 atm.

<h3>What is the pressure?</h3>

In this problem, we are mandated to obtain the pressure both by the use of the ideal gas equation and then the use of the Van der Walls equation.

Using the idea gas equation;

PV = nRT

P = nRT/V

P = pressure

V = volume

n = number of moles

T = temperature

R = gas constant

P = 1 * 0.082 * (24 + 273)/0.5

P = 48.7 atm

Using the Van Der Wall equation:

P = RT/(V - b) - a /V^2

P = 0.082 * 297/(0.5 - 0.03219) - 1.345/(0.5)^2

P = 24.354/0.46781 - 1.345/ /0.25

P = 52 - 5.38

P = 46.62 atm

The difference between the ideal pressure and the pressure calculated by the Van Der Waal equation is; 48.7 atm - 46.62 atm = 2.08 atm

Learn more about ideal gas equation:brainly.com/question/3637553

#SPJ1

8 0
2 years ago
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