Answer:
3 L
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 2 L
Initial pressure (P₁) = 0.75 atm
Final pressure (P₂) = 0.5 atm
Final volume (V₂) =?
Using the Boyle's law equation, the new volume (i.e final volume) of the Ne gas can be obtained as:
Initial volume (V₁) = 2 L
Initial pressure (P₁) = 0.75 atm
Final pressure (P₂) = 0.5 atm
Final volume (V₂) =?
P₁V₁ = P₂V₂
0.75 × 2 = 0.5 × V₂
1.5 = 0.5 × V₂
Divide both side by 0.5
V₂ = 1.5 / 0.5
V₂ = 3 L
Thus, the new volume of the Ne gas is 3 L
Answer: 1000 Hz
Explanation:
You can calculate frequency by dividing velocity by wavelength
Frequency = velocity/wavelength
Find velocity first.
900 m/3 s = 300 m/s
Plug values in to find frequency.
F = (300 m/s)/0.3 m
F = 1000 Hz
Yes, it is true, both mass spectrometry and infrared spectroscopy involve interaction of molecules with electromagnetic waves. ;Mass spectrometry method is used to determine the mass of a substance while infrared spectroscopy is used to determine the functional groups in molecules. Both methods involve the analysis of electromagnetic light interaction with molecules.
If two object experiences the same displacement at the same time, the two objects must have the same average velocity.
The average velocity of an object is defined as the change in displacement per change in time of motion. This can be written as follows;

If two object experiences the same displacement at the same time, it means that the change in displacement with time is constant.

Thus, we can conclude that if two object experiences the same displacement at the same time, the two objects must have the same average velocity.
Learn more here: brainly.com/question/23856383
Answer:
Y = Stress / Strain = (F / A) / (l / L) where l is the change in length
Since L is doubled and A remains the same one would expect l, the change in length to also double so Y remains the same.
As an example think of hanging a weight from a spring and the same weight from a similar spring of twice the length - one would expect the longer spring to show twice the extension of the shorter spring.