Explanation:
In an acid solution, the concentration of H₃O⁺ ions is more than OH⁻
In a basic solution, the concentration of OH⁻ is more than that of H₃O⁺
By definition:
According to Arrhenius theory;
An acid is a substance that interacts with water to produce excess hydroxonium ions, H₃O⁺ in an aqueous solution. The hydroxonium ions formed as a result of the chemical bonding between the oxygen of water molecules and the protons released by the acid due to its ionization.
A base is a substance that interacts with water to produce excess hydroxide ions, OH⁻ in an aqueous solution. The common bases are NaOH and KOH
learn more:
acid brainly.com/question/5121777
#learnwithBrainly
Someone very smart. definitely not me.
implement the following boolean function with an 8 to 1 line multiplexer and a single inverter F(A,B,C,D)=(2,3,5,6,8,9,12,14)
Fofino [41]
Examples of such quantities include distance, displacement, speed, velocity, acceleration, force, mass, momentum, energy, work, power, etc. All these quantities can by divided into two categories - vectors and scalars. A vector quantity is a quantity that is fully described by both magnitude and direction.
With the input of 68 J of energy, the temperature rises by 13 K, and the molar heat capacity of gallium is 25.86 J/(mol*K)
68 J * 25.86 J/(mol·K) * x mol=13 K
x=13/(68*25.86)=0.00739 mol
Molar mass of gallium is 69.723 g/mol, making the mass of this sample 0.515 g of gallium:
0.151 g = 68.723 g/mol * 0.00739 mol
The density of gallium is 5.91 g/cm^3, making the volume of this sample
0.872 cm^3 of gallium:
0.872 cm^3 = (0.515 g) / (5.91 g/cm^3)
Missing info in the text: the image is <em>inverted</em>
1) Magnification: -3
The magnification can be calculated with the equation
where
y' is the size of the image
y is the size of the object
In this problem, we have
y' = -60.0 mm (the sign is negative since the image is inverted)
y = 20.0 mm
Substituting,
2) Focal length: 0.862 m (converging)
We can also rewrite the magnification as follows
(1)
where
q is the distance of the image from the mirror
p is the distance of the image from the mirror
Here we know that the distance between the image and the object is 2.30 m, so
which means
Substituting into (1), we can find p:
And also q:
So now we can finally find the focal length by using the lens equation:
Where f is the focal length. Solving for f,
And since the focal length is positive, it means that the mirror is converging.