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3 years ago

I DARE YALL TO JOIN THIS MEET CODE IS cdabauer JOIN THEN HURRY UP AND LEAVE AND YOU WILL GET BRAINLY

Chemistry

2 answers:

serg [7]3 years ago

7 0

Answer:

Explanation:

Aleonysh [2.5K]3 years ago

4 0

Answer:

nah but ill take points tho

Explanation:

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True or False: A charged object has a surplus or deficiency of electrons

nadya68 [22]

Answer:

true I believe

Explanation: so sorry if this is wrong

3 0

3 years ago

When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 13.2 g of carbon were burned in the presence of

inessss [21]

C + O2 -> CO2
Oxygen is the excess reactant (doesn’t get used up in reaction, therefore mass of o2 is irrelevant) so use carbon (the limiting reactant) to calculate the mass of CO2

u should get 48.4g

4 0

3 years ago

Read 2 more answers

Calculate the moles of calcium chloride (CaCl2) needed to react in order to produce 85.00 grams of calcium carbonate (CaCO3). us

BartSMP [9]

Answer:

0.85 mole

Explanation:

Step 1:

The balanced equation for the reaction of CaCl2 to produce CaCO3. This is illustrated below:

When CaCl2 react with Na2CO3, CaCO3 is produced according to the balanced equation:

CaCl2 + Na2CO3 -> CaCO3 + 2NaCl

Step 2:

Conversion of 85g of CaCO3 to mole. This is illustrated below:

Molar Mass of CaCO3 = 40 + 12 + (16x3) = 40 + 12 + 48 = 100g/mol

Mass of CaCO3 = 85g

Moles of CaCO3 =?

Number of mole = Mass /Molar Mass

Mole of CaCO3 = 85/100

Mole of caco= 0.85 mole

Step 3:

Determination of the number of mole of CaCl2 needed to produce 85g (i.e 0. 85 mole) of CaCO3.

This is illustrated below :

From the balanced equation above,

1 mole of CaCl2 reacted to produced 1 mole of CaCO3.

Therefore, 0.85 mole of CaCl2 will also react to produce 0.85 mole of CaCO3.

From the calculations made above, 0.85 mole of CaCl2 is needed to produce 85g of CaCO3

5 0

3 years ago

Read 2 more answers

Question 6

Hoochie [10]

Answer:

Explanation:

Area of a circular hubcap is 615 square inches

Area of a circular shaped object is given by :

$A=\pi r^2$

r is radius of hubcap.

If the radius of the hubcap were quadrupled, it means r' = 4r. New area will become:

$\dfrac{A}{A'}=\dfrac{r^2}{r'^2}$

A' is new area

$A'=A\times \dfrac{r'^2}{r^2}\\\\A'=615\times \dfrac{(4r)^2}{r^2}\\\\A'=615\times 16\\\\A'=9840\ \text{inches}^2$

New area of the hubcap is 9840 square inches.

6 0

3 years ago

The purpose of a coal burning power plant is to produce which end product?

Mice21 [21]

Answer:

The purpose of a coal burning power plant is to produce electricity so its A

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3 years ago

I DARE YALL TO JOIN THIS MEET CODE IS cdabauer JOIN THEN HURRY UP AND LEAVE AND YOU WILL GET BRAINLY​

I DARE YALL TO JOIN THIS MEET CODE IS cdabauer JOIN THEN HURRY UP AND LEAVE AND YOU WILL GET BRAINLY