Answer:
the equilibrium temperature Te = 19.9°C
Explanation:
Given;
specific heat for copper Cc is 390 J/kg⋅°C
for aluminun Ca is 900 J/kg⋅°C,
for water Cw is 4186 J/kg⋅°C
Mass of copper Mc= 265 g = 0.265kg
Temperature of copper Tc = 235°C
Mass of aluminium Ma = 135g = 0.135 kg
Temperature of aluminium Ta = 14.0°C
Mass of water Mw= 865 g = 0.865kg
Temperature of water Tw = 14.0°C
The equilibrium temperature can be derived by;
Te = (MaCaTa + McCcTc + MwCwTw)/(MaCa + McCc+ MwTw)
Substituting the values;
Te = ( 0.135×900×14 + 0.265×390×235 + 0.865×4186×14)/(0.135×900 + 0.265×390 + 0.865×4186)
Te = 19.939°C
Te = 19.9°C
The correct answer to the question is: Sound wave.
EXPLANATION:
Before going to answer this question, first we have to understand longitudinal wave.
A longitudinal wave is a mechanical wave in which the direction of propagation of wave is parallel to the direction of particle vibration.
This wave propagates through a medium in the form of compression and rarefaction.
Compression are the regions of high pressure zones where the particles of the medium are closely aggregated to each other.
Rarefaction is the region of low pressure where particles of the medium are not so close to each other as compared to compression.
The longitudinal wave can not propagate in space. It always needs a medium for it's propagation. The medium may be solid, liquid or gas .
For instance, sound wave is a longitudinal wave.
Hence, the correct answer of this question is sound wave which needs a medium for it's propagation.
Answer:
yeah
Explanation:
as wavelength increases frequency decreases and it goes the same for the opposite way
Answer:
Explanation:
Let x₀ be the amplitude , ω be the angular velocity
velocity at displacement x ,
v = ω 
at 
v = ω [ 
v² = ω² x
1/2 m v²
= 3/8 m x ω²x₀²
Total energy = 1/2 m ω²x₀²
Kinetic energy as fraction of total energy
= 3/8 m x ω²x₀² x 2 / m ω²x₀²
= 3 / 4
Fraction of potential energy
= 1 - 3/4
1/4
c )
Half kinetic = half potential energy
= 1/4 m ω²x₀²
1/2 m ω²( x₀²- x ² )
x₀²/2 = x₀²- x ²
x² = x₀²/2
x = x₀/√2
If the rock is just sitting there and you want to SLIDE it, then you have to push it with a force of at least
(251 kg) x (9.8 m/s²) x (μ) =
(2,459 Newtons) x (the coefficient of static friction on that surface)