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Luden [163]
3 years ago
10

Describe the direction of the forces you would exert in the Sim to make the orange object reach the target without

Physics
1 answer:
Novosadov [1.4K]3 years ago
7 0
HELPPPPPPPPPPPPPPPPPPPPPPP HELPPPPPPPPPPPPPPPPPPPPPPP the same time as the first
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Which of these has components that can have a varying ratio?
Travka [436]
I say C. But I’m not 100% sure so check it first
6 0
3 years ago
Pleaseeee helppppppp​
vredina [299]

Answer:

the vertical acceleration is 9.8 m/s,

downward and no horizontal acceleration..

7 0
3 years ago
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Hot water is poured into a mug and the mug gets hot. This is an example of which type of energy transfer?
Korolek [52]

The answer is B: Conduction

5 0
3 years ago
A carnot heat engine receives 600 kj of heat from a source of unknown temperature and rejects 175 kj of it to a sink at 20°c. de
oee [108]

(b) 71%

The thermal efficiency of a Carnot heat engine is given by:

\eta = \frac{W}{Q_{in}}

where

W is the useful work done by the engine

Q_{in} is the heat in input to the machine

In this problem, we have:

Q_{in}=600 kJ is the heat absorbed

W=600 kJ-175 kJ=425 kJ is the work done (175 kJ is the heat released to the sink, therefore the work done is equal to the difference between the heat in input and the heat released)

So, the efficiency is

\eta = \frac{425 kJ}{600 kJ}=0.71 = 71\%

(a) 737^{\circ}C

The efficiency of an engine can also be rewritten as

\eta = 1-\frac{T_C}{T_H}

where

T_C is the absolute temperature of the cold sink

T_H is the temperature of the source

In this problem, the temperature of the sink is

T_C = 20^{\circ}C + 273=293 K

So we can re-arrange the equation to find the temperature of the source:

T_H = \frac{T_C}{1-\eta}=\frac{293 K}{1-0.71}=1010 K\\T_H = 1010 K - 273=737^{\circ}C

7 0
3 years ago
In how many ways can the elements of [n] be permuted if 1 must precede 2 and 3 is to precede 4?
sp2606 [1]

No. of ways in the elements of n be permuted is  n!/4

Number of elements = n

Number of face in which the element of n be permuted if 1 must proceed 2 and 3 is to precede 4.

n =  4

The possible permutation will

(1,2,3,4), (1,3,2,4),(1,3,4,2),(3,4,1,2),(3,1,2,4),(3,1,4,2)

There are 6 possible outcomes

For n= 5

With 1,2,3,4 we add 5 in the arrangement with above terms

The possible number of permutation

5×6 = 30

When n = 6

30×6 = 180.

So for an element

If 1 precede 2 and 3 is yo precede 4 is

<h2>\frac{n*(n-1)*(n-2) ........ 6*5*6*4!}{4!}</h2>

= n! ×6/4!

= n!/4

No. of ways in the elements of n be permuted is  n!/4

To know more about permutation:

brainly.com/question/4416319

#SPJ4

4 0
2 years ago
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