Given :
A rope 6m long is fixed at one end, the other end is attached to a light string so that it is free to move.
The speed of waves on the rope is 18 m/s.
To Find :
The frequency of the second harmonic.
Solution :
We know, for second harmonic wave :
Wavelength = Length of rope

Now, we know frequency is given by :

Therefore, the frequency of the second harmonic is 3 s⁻¹.
Answer:
tug_tug = 570 10³ l
Explanation:
In this problem, each propeller creates a force that makes the boat rotate, so the tugs have to create a die of equal magnitude rep from the opposite direction
∑ τ = 0
F1 la+ (-F1) (-l) = τ-tug
τ-tug = 2 f1 l
τ-tug = 2 28510³ l
tug_tug = 570 10³ l
where the is the distance from the propane axis to the point where the ship turns
This force may be less depending on where the tug is.
Answer:
the force decreases
Explanation:
Gravitational force is depending on it's mass and the distance between two object
The attachment shows us to understand relationship of it's
F ∝ 1/ (r)2
there for gravitational force is inversely proportional to it's distance . when distance between two object is increased, Then force will be decreased
Answer:
When force is applied to an object it causes to to accelerate.
Explanation:
73 Newton is the correct answer