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AveGali [126]
4 years ago
6

An astronaut on a spacewalk accidentally drops a tool, and it floats away.Which of the following objects is exerting a gravitati

onal force on the floating tool? Choose all that apply
the astronaut
the Moon
the Earth
the Sun
Physics
2 answers:
castortr0y [4]4 years ago
4 0

Answer:

All of them are correct

Explanation:

They are all correct select all

a_sh-v [17]4 years ago
3 0

Gravitational force is given as

F = \frac{Gm_1m_2}{r^2}

so here gravitational force will be given by above formula where the force between two objects depends on the mass of two objects and distance between them.

Now here since the tool is at finite distance from Astronaut and Moon, Sun, Earth

So all the above will exert gravitational force on the tool but the magnitude of force will be different as all of the above are of different masses and situated at different distance.

So all options are correct here

The Astronaut

The Moon

The Sun

The Earth

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The weights of soy patties sold by a diner are normally distributed. A random sample of 15 patties yields a mean weight of 3.8 o
shepuryov [24]

Complete Question

The weights of soy patties sold by a diner are normally distributed. A random sample of 15 patties yields a mean weight of 3.8 ounces with a sample standard deviation of 0.5 ounces. At the 0.05 level of significance,perform a hypothesis test to see if the true mean weight is  less than 4 ounce.

Answer:

Yes the true mean weight is less than 4 ounce

Explanation:

  From the question we are told that

     The random sample is n = 15

       The mean weight is \= x = 3.8\  ounce

        The standard deviation is  \sigma = 0.5 \ ounce

         The  level of significance is  \alpha  = 0.05

       

So

   The  null hypothesis is  H_o : \mu \ge 4

     The alternative hypothesis is H_a : \mu < 4

Generally the critical value which a bench mark to ascertain whether the null hypothesis is  true or false is mathematically represented as

            t_{0.05} = 1.79

This value is  obtained from  the critical value table

Generally the test statistics is mathematically represented as

                Test \ Statistics (ST)  = \frac{\= x - \mu }{\frac{\sigma}{\sqrt{n} }  }

           =>  ST = \frac{3.8 -4 }{\frac{0.5}{\sqrt{20} } }

                ST = - 1.79

So since ST is less than t_{0.05}  then the null hypothesis would be rejected and the alternative hypothesis would be accepted so

  Thus the true mean weight is less than 4

4 0
3 years ago
A 10cm spring is hung from a clamp stand. With 1N of force it measures 12.2cm long and with 3N of force it measures 16.4cm long.
solmaris [256]

Answer:

0.48 N/cm

Explanation:

The original length is 10cm so with a force of 10cm, the extension will be 12.2-10=2.2 cm when force of 1N is exerted. Similarly, with a force of 3N, the extension is 16.4-10=6.4cm

The slope will be given by change in force/ change in extension and this is equivalent to the stiffness.

Change in force is 3-1=2 N

Change in exgension is 6.4-2.2=4.2 cm

The slope will be 2/4.2=0.4761904761904 N/cm

Rounded off, the slope is 0.48 N/cm and this is the stiffness of the spring.

7 0
4 years ago
Two equal forces act on two different objects, one of which has a mass ten times as large as the other. The larger object will h
elena-s [515]

Answer:

The larger object will have <u>smaller</u>  acceleration that the less massive object.

Explanation:

Generally force is mathematically represented as

      F =  ma

=>  m  =  \frac{F}{a }

at constant  force  we have

     m  \  \alpha  \  \frac{1}{a}

So if  m is  increasing a will be decreasing which means the object with the larger mass will have less acceleration

4 0
3 years ago
Look at the picture to answer :)
cricket20 [7]

Answer:

The stress of the movement of tectonic plates caused this fold.

Sorry I don't know the answer to the first part.

3 0
3 years ago
If an object is 413 Kg in mass and 640 M3. What is the density? Will It Float?
monitta

Answer:

The density will be 0.65 kg/m3

I think it won't float!! I am not sure though.

7 0
3 years ago
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