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3 years ago

Use the drop-down menus to complete the statements.

Physics

1 answer:

jekas [21]3 years ago

4 0

Answer:

Use the drop-down menus to complete the statements.

When electrons are lost, a

✔ positive

ion is formed.

When electrons are gained, a

✔ negative

ion is formed.

Explanation:

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A train goes 25000 m East in 1500 sec and then turns around and travels 29,000 m West for 1740 sec. Determine the distance, spee

eimsori [14]

Answer:

scalar d = 54000 m , v_average = 16,667 m / s

vector d = -4000 m , moved 4000 to the west

v_average = 0

Explanation:

his is a uniform motion exercise, but we must be careful with quantities that are scalars and vector quantities

The distance traveled is a scalar

d = d₁ + d₂

d = 25000 + 29000

d = 54000 m

the speed is a scalar, in the exercise it is not specified if the speed of each trajectory or the average speed. Therefore we will calculate the two

v₁ = d₁ / t₁

v₁ = 25000/1500

v₁ = 16,667 m / s

v₂ = 29000/1740

v₂ = 16,667 m / s

Since the two speeds are equal, the average speed is

v = (v1 + v2) / 2

v_average = 16,667 m / s

now let's calculate the displacement that is a vector, so it has direction in addition to modules

suppose the eastward direction is positive and the bold are vectors

d = d₁ - d₂

d = 25000 - 29000

d = -4000 m

this means that it moved 4000 to the west

velocity is a vector, we assume positive eastward movement

v₁ = 16,667 m / s

v₂ = - 16,667 m / s

v_average = (v1 -v2) / 2

v_average = 0

5 0

4 years ago

Using energy considerations, calculate the average force (in N) a 62.0 kg sprinter exerts backward on the track to accelerate fr

slava [35]

Answer:

69.68 N

Explanation:

Work done is equal to change in kinetic energy

W = ΔK = Kf - Ki = $\frac{1}{2} mv^{2} _{f} - \frac{1}{2} mv^{2} _{i}$

W = $F_{total} .d$

where m = mass of the sprinter

vf = final velocity

vi = initial velocity

W = workdone

kf = final kinetic energy

ki = initial kinetic energy

d = distance traveled

Ftotal = total force

vf = 8m/s

vi= 2m/s

d = 25m

m = 60kg

inserting parameters to get:

W = ΔK = Kf - Ki = $\frac{1}{2} mv^{2} _{f} - \frac{1}{2} mv^{2} _{i}$

$F_{total} .d =\frac{1}{2} mv^{2} _{f} - \frac{1}{2} mv^{2} _{i}$

$F_{total} = \frac{\frac{1}{2} mv^{2} _{f} - \frac{1}{2} mv^{2} _{i}}{d}$

$F_{total=} \frac{\frac{1}{2} X 62 X6^{2} -\frac{1}{2} X 62 X2^{2} }{25}$

= 39.7

we know that the force the sprinter exerted F sprinter, the force of the headwind Fwind = 30N

$F_{sprinter} = F_{total} + F_{wind} = 39.7 + 30 = 69.68 N$

7 0

3 years ago

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Maple syrup, which comes from the sap of maple trees, contains water and natural sugars. It's a clear, brown liquid and the suga

Amanda [17]

The answer would be colloid

7 0

3 years ago

The established value for the speed of light in a vacuum is 299,792,458 m/s. What is the order-of-magnitude of this number?

iogann1982 [59]

The order of magnitude is 10⁸ .

6 0

4 years ago

Write the function y(x, t) that describes this pulse if it is traveling in the positive x-direction with a speed of 2.10 m/s. (U

Marrrta [24]

Answer:

The function is missing in the question. The function of the transverse pulse in the wire is given by $y=\frac{6}{x^2 +3}$

Explanation:

A transverse wave can be defined as the wave whose direction of displacement is always perpendicular to the direction of propagation. For example, surface wave at water bodies. While a pulse can be defined as a sudden change in a constant quantity such as a pulse of the radiation or current.

Let the wire of infinite length in both the directions and also the magnitude of deflection of wire be in the same shape except the point of maximum deflection to move along the wire.

Thus the equation of the pulse moving the in the positive x-direction moving at the speed of 2.10 m/s is

$y=\frac{6}{(x-2.10)^2 +3}$ .

8 0

3 years ago