Answer:
-255.4 kJ
Explanation:
The free energy of a reversible reaction can be calculated by:
ΔG = (ΔG° + RTlnQ)*n
Where R is the gas constant (8.314x10⁻³ kJ/mol.K), T is the temperature in K, n is the number of moles of the products (n =1), and Q is the reaction quotient, which is calculated based on the multiplication of partial pressures by the partial pressure of the products elevated by their coefficient divide by the multiplication of the partial pressure of the reactants elevated by their coefficients.
C₂H₂(g) + 2H₂(g) ⇄ C₂H₆(g)
Q = pC₂H₆/[pC₂H₂ * (pH₂)²]
Q = 0.261/[8.58*(3.06)²]
Q = 3.2487x10⁻³
ΔG = -241.2 + 8.314x10⁻³x298*ln(3.2487x10⁻³)
ΔG = -255.4 kJ
The empirical formula is the simplest form of the formula expressed in the lowest ratio. In this case, we just have to divide each subscript by the greatest common factor. Hence.
a. CN
b. P2O5
c.N2O5
d.NaCl
e. C9H20
f. BH3
g.K2Cr2O7
h.AlB3
i.CH
j.SiCl4
Greatest is at W because kendrick is still and it’s at the highest point.. x has greatest gravitational because it’s closest to the ground.. potential energy is at Z because it’s going straight so it’s stil moving
Answer:
The conditions for biochemical, chemical and both standard states are shown below
Explanation:
Chemical standard state:
Temperature is 25°
Intial concntration of reactants and products is 1M
g. Presurre is 1 atm.
PH7
Biochemical standard state:
Temperature is 25°
PH7
Constant value of Mg2+
Both:
Intial concntration of reactants and products is 1M
g. Presurre is 1 atm.
Temperature is 25°
PH7
