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Oxana [17]
3 years ago
6

Who is the target group of referred to or described in the text about gabu?

Physics
1 answer:
Oxana [17]3 years ago
5 0
The target group of readers is anyone who reads the text, which means that everyone is the target group
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The idea that people behave in odd ways on a full moon is an example of a limitation of science. a characteristic of science. ps
ludmilkaskok [199]

Answer:

Pseudoscience

Explanation:

Because its is based on beliefs with a explanation

5 0
4 years ago
Read 2 more answers
An athlete performing a long jump leaves the ground at a 32.9 ∘ angle and lands 7.78 m away.part a )what was the takeoff speed ?
MatroZZZ [7]

Answer:

Explanation:

Given

Inclination \theta =32.9^{\circ}

Distance of landing point R=7.78\ m

Considering athlete to be an Projectile

range of projectile is given by

R=\frac{u^2\sin 2\theta }{g}

where u=launch velocity

7.78=\frac{u^2\sin (2\times 32.9)}{9.8}

u^2=83.58

u=\sqrt{83.58}

u=9.142\ m/s

(b)If u is increased by 8% then

new velocity is u'=9.87\ m/s

R'=\frac{u'^2\sin 2\theta }{g}

R'=9.07\ m

 

3 0
4 years ago
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A fly is call inside a car that is moving in the positive direction with constant velocity. The fly flies with a constant veloci
balu736 [363]
A. The fly's velocity to the ground is less than the car's velocity to the ground.
4 0
4 years ago
Say that you are in a large room at temperature TC = 300 K. Someone gives you a pot of hot soup at a temperature of TH = 340 K.
lora16 [44]

Answer:

Explanation:

Heat energy given out by the soup

= C_v  x ( t₂ - t₁ )

= 33 x ( 340 - 300)

= 1320 J

This heat is given to Carnot engine . Efficiency of engine

= (340 - 300 ) / 340

= 40 / 340

2 / 17

This fraction of total heat given is converted into useable work by the engine.

5 0
4 years ago
A 0.040kg block of of copper at 95℃ is placed in 0.105kg of water at an unknown temperature. After equilibrium is reached, the f
Rainbow [258]

Answer:

Explanation:

heat lost by block of copper

= mass x specific heat x fall in temperature

= .04 x 385 x ( 95 - 24 )

= 1093.4 J

Heat gained by water

= .105 x 4200 x ( 24 - T ) ;  Here T is initial temperature of water .

= 441 ( 24 - T )

heat lost = heat gained

1093.4 = 441 ( 24 - T )

24 - T = 2.48

T = 21.52 ℃

3 0
3 years ago
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