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Zepler [3.9K]
2 years ago
12

245289457u2895785/+55891235723895718957=

Physics
2 answers:
Bingel [31]2 years ago
6 0

<em>why Is there just a random "u" in the middle of the equation </em><em>awa</em><em> </em>

<em> </em><em>t</em><em>h</em><em>e</em><em>question is impossible to do btw </em>

<em>Imao the u in the middle doesn't makes sense </em>

if<em> you edit the question I'll help you w it)</em>

have a good day bro cya

Snezhnost [94]2 years ago
6 0

Answer:

Thxs for the points

Explanation:

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What two kinds of crust are involved in a subduction zone
Anarel [89]

Answer:

Oceanic crust and continental crust

Explanation:

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5 0
3 years ago
. An object whose mass is 375 lb falls freely under the influence of gravity from an initial elevation of 253 ft above the surfa
lozanna [386]

Answer:

(a) Vf = 128 ft/s

(b) K.E = 122.8 Btu

Explanation:

(a)

In order to find the velocity of the object just before striking the surface of earth or the final velocity, we use 3rd equation of motion:

2gh = Vf² - Vi²

where,

g = 32.2 ft/s²

h = height = 253 ft

Vf = Final Velocity = ?

Vi = Initial Velocity = 10 ft/s

Therefore,

(2)(32.2 ft/s²)(253 ft) = Vf² - (10 ft/s)²

16293.2 ft²/s² + 100 ft²/s² = Vf²

Vf = √(16393.2 ft²/s²)

<u>Vf = 128 ft/s</u>

<u></u>

(b)

The kinetic energy of the object before it hits the surface of earth is given by:

K.E = (0.5)(m)(Vf)²

where,

m = mass of object = 375 lb

K.E = Kinetic energy of object before it strikes the surface of earth = ?

Therefore,

K.E = (0.5)(375 lb)(128 ft/s)²

K.E = 3073725 lb.ft²/s²

Now, converting this to Btu:

K.E = (3073725 lb.ft²/s²)(1 Btu/25037 lb.ft²/s²)

<u>K.E = 122.8 Btu</u>

3 0
4 years ago
Candice is examining a cell under a microscope. She has identified a cell wall, a nucleus, and a chloroplast. What type of organ
RoseWind [281]

Answer:

A plant

Explanation:

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