Input the atomic masses of Mg and P to give 134.84g/mol
Explanation:
The molar mass of a substance (atom or molecule or compound) is the mass in grams of one mole of the substance:
When dealing with an element the molar mass is the relative atomic mass expressed as g/mol.
For compounds, you add the atomic masses of the component atoms and you sum up.
You simply input the atomic mass of 3 atoms of Mg and 2 atoms of P
Atomic mass of Mg = 24.3g/mol
P = 30.97g/mole
Molar mass of Mg₃P₂ = 3(24.3) + 2(30.97) = 134.84g/mol
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Answer: The correct answer is Hydrogen Fluoride.
Answer:
a. -0.63 V
b. No
Explanation:
Step 1: Given data
- Standard reduction potential of the anode (E°red): -1.33 V
- Minimum standard cell potential (E°cell): 0.70 V
Step 2: Calculate the required standard reduction potential of the cathode
The galvanic cell must provide at least 0.70V of electrical power, that is:
E°cell > 0.70 V [1]
We can calculate the standard reduction potential of the cathode (E°cat) using the following expression.
E°cell = E°cat - E°an [2]
If we combine [1] and [2], we get,
E°cat - E°an > 0.70 V
E°cat > 0.70 V + E°an
E°cat > 0.70 V + (-1.33 V)
E°cat > -0.63 V
The minimum E°cat is -0.63 V and there is no maximum E°cat.
The answer would be B) Absolute time.
