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Sindrei [870]
3 years ago
6

Two boxes (24 kg and 62 kg) are being pushed across a horizontal frictionless surface, as the drawing shows. The 36-N pushing fo

rce ModifyingAbove Upper P With right-arrow is horizontal and is applied to the 24-kg box, which in turn pushes against the 62-kg box. Find the magnitude of the force ModifyingAbove Upper F With right-arrow that the 24-kg box applies to the 62-kg box.
Physics
1 answer:
defon3 years ago
6 0

Answer:

F = 26.04 N

Explanation:

As we know that system of two boxes are moving on frictionless surface

So here if two boxes are considered as a system

then we have

F = (m_1 + m_2) a

m_1 = 24 kg

m_2 = 62 kg

F = 36 N

36 = (24 + 62) a

a = 0.42 m/s^2

Now since we know that both the boxes are moving together so force applied by first box on other box is given as

F = ma

F = (62 \times 0.42)

F = 26.04 N

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When an object moves its length contracts in the direction of motion. The faster it moves the shorter it gets in the direction of motion.
The object in this question moves and then stops moving. So it's length first contracts and then expands to its original length when the motion stops.
The speed doesn't have to be anywhere near the speed of light. When the object moves its length contracts no matter how fast or slow it's moving.
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4 years ago
A toy rocket launcher can project a toy rocket at a speed as high as 35.0 m/s.
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Answer:

(a) 62.5 m

(b) 7.14 s

Explanation:

initial speed, u = 35 m/s

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Use third equation of motion

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0^{2}=35^{2}- 2 \times 9.8 \times h

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Thus, the rocket goes upto a height of 62.5 m.

(b) Let the rocket takes time t to reach to maximum height.

By use of first equation of motion

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0 = 35 - 9.8 t

t = 3.57 s

The total time spent by the rocket in air = 2 t = 2 x 3.57 = 7.14 second.

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3 years ago
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Speed of a plane a is 900 km/h and that of plane b is 50 km/h. So, we can say that plane a is moving faster.

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