Two boxes (24 kg and 62 kg) are being pushed across a horizontal frictionless surface, as the drawing shows. The 36-N pushing fo
1 answer:
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Answer:
Explanation:
The torque applied on an object can be calculated by the following formula:
where,
T = Torque
F = Applied Force
r = radius of the wheel
For car wheel:
For truck wheel:
Dividing both:
for the same force applied on both wheels:
where,
rt = radius of the truck steering wheel = 0.25 m
rc = radius of the car steering wheel = 0.19 m
Therefore,
Answer:
(a) 0 J
(b) 828.96 J
(c) 828.96 J
(d) 828.96 J
(e) 0 J
(f) 828.96 J
Explanation:
Given:
Mass of the rock is,
Initial height of the rock is,
Final height of the rock is,
Initial velocity of the rock is,
Acceleration due to gravity is,
(a)
Initial kinetic energy is given as:
Plug in the given values and solve for ''. This gives,
Therefore, initial kinetic energy is 0 J.
(b)
Initial potential energy is given as:
Therefore, initial potential energy is 828.96 J.
(c)
Mechanical energy is equal to the sum of kinetic and potential energy. It is always a constant value. Therefore,
Therefore, mechanical energy at 26.6 m is 828.96 J.
(d)
Now, at the final height of 0 m, the decrease in potential energy will be equal to the increase in the kinetic energy. In other words, the potential energy at the start will be converted to kinetic energy at the bottom.
Therefore, kinetic energy at the 0 m is given as:
(e)
Potential energy at the final height is given as:
Therefore, final potential energy is 0 J.
(f)
Total mechanical energy is a constant and doesn't depend on the height.
So, total mechanical energy at 0 m is same as that at 26.6 m.
Total mechanical energy is 828.96 J.