D is the point where the planet moves the fastest. This is because it is in the perihelion, where the planet is moving at it’s fastest pace
Answer:
because speed is the modulus of velocity which is a vector
the velocity to be zero it must be a round trip
Explanation:
This is because speed is the modulus of velocity which is a vector.
For the velocity to be zero it must be a round trip, therefore the resulting vector zero
On the other hand, the speed of the module is the same in both directions
Answer:
I_v = 2,700 W / m^2
I_m = 610 W / m^2
I_s = 16 W / m^2
Explanation:
Given:
- The Power of EM waves emitted by Sun P_s = 4.0*10^26 W
- Radius of Venus r_v = 1.08 * 10^11 m
- Radius of Mars r_m = 2.28 * 10^11 m
- Radius of Saturn r_s = 1.43 * 10^12 m
Find:
Determine the intensity of electromagnetic waves from the sun just outside the atmospheres of (a) Venus, (b) Mars, and (c) Saturn.
Solution:
- We know that Power is related to intensity and surface area of an object follows:
I = P / 4*pi*r^2
Where, A is the surface area of a sphere models the atmosphere around the planets.
a)
- The intensity at the surface of Venus is calculated as:
I_v = P_s / 4*pi*r^2_v
I_v = 4.0*10^26 / 4*pi*(1.08*10^11)^2
I_v = 2,700 W / m^2
b)
- The intensity at the surface of Mars is calculated as:
I_m = P_s / 4*pi*r^2_m
I_m = 4.0*10^26 / 4*pi*(2.28*10^11)^2
I_m = 610 W / m^2
c)
- The intensity at the surface of Saturn is calculated as:
I_s = P_s / 4*pi*r^2_s
I_s = 4.0*10^26 / 4*pi*(1.43*10^12)^2
I_s = 16 W / m^2
Answer:
<u><em>375 J</em></u>
Explanation:
<u><em>Total energy</em></u> = 750 J
<u><em>Efficiency</em></u> = 50%
<u><em>Wasted energy</em></u> = 50% [100% - 50%]
<u><em>Amount of wasted energy</em></u>
= 750 x 50%
= 750 x 0.5
= 375 J
