Answer:
calorimeter is the device used to measure heat reaction
<h2>Answer: Ultraviolet Light
</h2>
Ultraviolet light, whose wavelength is approximately between 100 nm and 380 nm; is a type of electromagnetic radiation that is not visible to the human eye.
This light is used for many purposes, among which is the identification of fluerescent minerals.
In this sense, fluorescence is a property that certain materials have in which they absorb energy in the form of short wavelength not visible electromagnetic radiation (the ultraviolet, for example) and then emit some of that energy in the form of longer wavelength electromagnetic radiation (in the visible spectrum). This is also called luminiscence.
Hence, the correct option is a.
Yes, because electric charges have electric field surrounding them that allow them to exert forces on other objects without touching them.
Answer:
Grams of water can be heated from 20.0°C to 75°C using 12500.0 Joules = 54.3 g
Explanation:
Heat required to increase temperature
H = mcΔT
m = mass of material
C = specific heat of material
ΔT = Change in temperature.
Here we need to find how many grams of water can be heated from 20.0°C to 75°C using 12500.0 Joules
That is
H = 12500 J
Specific heat of water, C = 4186 J/kg°C
ΔT = 75 - 20 = 55
Substituting
12500 = m x 4186 x 55
m = 0.0543 kg
m = 54.3 g
Grams of water can be heated from 20.0°C to 75°C using 12500.0 Joules = 54.3 g
The equation of GPE is mgH, where m is mass, g is gravitational acceleration, and H is the height.
If we're solving for the change in GPE, then:
∆
= mg∆H
<u>Input our given values for m and g:</u>
∆ = 0.25 * 9.80 * ∆H
<u>The book falls from 2 meters high to 0.5 meters high, so:</u>
∆ = 0.25 * 9.80 * (2.0 - 0.5)
∆ = 0.25 * 9.80 * 1.5
∆ = 3.675 (J)
<u>Adjust for significant figures:</u>
∆ = 3.7 (J)
The change in gravitational potential energy was 3.7 (J)
If you have any questions on anything I did to get to the answer, just ask!
- breezyツ
