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Zepler [3.9K]
3 years ago
15

What is gravity? Pkz answer will mark brainliest.​

Physics
2 answers:
mixas84 [53]3 years ago
7 0

Answer:

the force that attracts a body toward the center of the earth, or toward any other physical body having mass.

mixer [17]3 years ago
5 0

Answer:

Answer in Explanation

Explanation:

Gravity is a force that attracts a body toward the center of the earth, or toward any other physical body having mass. Plz mark me brainliest....

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Supercells are updrafts that may cause which of the following?
ale4655 [162]

just for anyone looking for the answer i just took the test and the answer is tornadoes

6 0
3 years ago
What is the magnitude and direction (right or left) of the
Sunny_sXe [5.5K]

Answer: 12 N to the right

Explanation:

If we calculate the net force acting on the box, we will have:

<u>In y-component:</u>

Fy_{net}=F_{n}+F_{g} (1)

Where F_{n}=12 N is the Normal force, directed upwards and F_{g}=-12 N is the weight of the box (gravity force), directed downwards.

Fy_{net}=12 N-12 N (2)

Fy_{net}=0 N (3) Hence the net force in the vertical component is zero

<u>In x-component:</u>

Fx_{net}=F_{left}+F_{right} (4)

Where F_{left}=-3 N and F_{right}= 15 N

Fx_{net}=-3 N + 15 N (5)

Fx_{net}=12 N (6) This is the net force in the horizontal component

Therefore, the total net force acting on the box is 12 N directed to the right

5 0
3 years ago
If the amount of work done was 6 joules on an object and the object was moved 30m,
Nonamiya [84]

Answer:

180

Explanation:

Work done= Force x distance

<u>So rearrange the formula to find the force</u>

Force= Work done/distance

Force= 6/30

Force= 1/5 N or 0.2 N

5 0
3 years ago
A. 7cm<br>B. 24cm<br>C. 18cm<br>D. 63cm​
Alex17521 [72]

Answer:

A. 7cm

I hope it helps...

6 0
3 years ago
Three children are struggling and pulling on a single toy. Two of the children, Abe and Barry, are EACH (individually) pulling w
3241004551 [841]

Solution :

c). $\vec{F}_A = $ force applied by Abe

   $\vec{F}_B = $ force applied by Barry

   $\vec{F}_E = $ force applied by Eric

   $\vec{F}_R = $ Resultant force

$\vec{F}_A $  in the vector form can be written as :

         $\vec{F}_A = 0 \hat{i} + 60 \hat{j}$

$\vec{F}_B $  in the vector form can be written as :

         $\vec{F}_B = 60 \hat{i} + 0 \hat{j}$

The resultant,

$\vec{F}_R= \vec{F}_A+\vec{F}_B $

     $=(0 \hat i + 60 \hat j)+(60 \hat i + 0\hat j)$

    $=60 \hat i + 60 \hat j$

$|\vec{F}_R| = \sqrt{60^2+60^2}$

        = 84.853 N

d). As the three forces are in equilibrium, therefore,

$|\vec F_E| = |\vec F_R|$

$|\vec F_E| =84.853 \ N$

e). The direction of the force exerted by Eric is exactly opposite to the direction of the resultant force.

The direction of the resultant force is :

$\theta = \tan ^{-1}\left(\frac{F_y}{F_x}\right)$

   $ = \tan ^{-1}\left(\frac{60}{60}\right)$

  = 45°  north east

The direction of the force E is  45° west or  45° south west.

   

8 0
3 years ago
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