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olchik [2.2K]
4 years ago
15

A fire hose held near the ground shoots water at a speed of 6.5 m/s. At what angle(s) should the nozzle point in order that the

water land 2.5 m away (Fig. 3–36)? Why are there two different angles? Sketch the two trajectories.
Physics
1 answer:
Mariana [72]4 years ago
8 0

Answer:

17.72° or 72.28°

Explanation:

u = 6.5 m/s

R = 2.5 m

Let the angle of projection is θ.

Use the formula for the horizontal range

R=\frac{u^{2}Sin2\theta }{g}

2.5=\frac{6.5^{2}Sin2\theta }{9.8}

Sin 2θ = 0.58

2θ = 35.5°

θ = 17.72°

As we know that the range is same for the two angles which are complementary to each other.

So, the other angle is 90° - 17.72° = 72.28°

Thus, the two angles of projection are 17.72° or 72.28°.

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A 30-cm long string, with one end clamped and the other free to move transversely, is vibrating in its second harmonic. The wave
Ann [662]

Answer:

\lambda = 40 cm

Explanation:

given data

string length = 30 cm

solution

we take here equation of length that is

L = n \times \frac{1}{4} \lambda     ...............1

so

total length will be here

L = \frac{\lambda}{2} +  \frac{\lambda}{4}\\

L = \frac{3 \lambda }{4}

so \lambda  will be

\lambda = \frac{4L}{3}\\\lambda = \frac{4\times 30}{3}

\lambda = 40 cm

5 0
3 years ago
Explain the causes of yaa asantewaa war of 1900​
Anna11 [10]

Answer: the conflict began when a british representative - Sr. Frederick Mitchell Hodgson sat on the golden stool.

Explanation:

since the stool wasn't a throne, when Yaa Asantewaa found out, he led a rebellion which killed 1000 British and allied African soldiers and 2,000 Ashanti.      

good luck with your assignment :)

8 0
3 years ago
Two children, Ferdinand and Isabella, are playing with a waterhose on a sunny summer day. Isabella is holding the hose in herhan
sweet [91]

Answer:

84.196%

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

y_0=1\ m

x = 10 m

t = Time taken

v_0 = 3.5 m/s (assumed, as it is not given)

A_0 = \pi 1.5^2

We have the equation

y=y_0+ut+\dfrac{1}{2}gt^2\\\Rightarrow 0=y_0-\dfrac{1}{2}gt^2\\\Rightarrow t=\sqrt{\dfrac{2y_0}{g}}\\\Rightarrow t=\sqrt{\dfrac{2\times 1}{9.81}}\\\Rightarrow t=0.45152\ s

x=x_0+vt\\\Rightarrow 10=0+v0.45152\\\Rightarrow v=\dfrac{10}{0.45152}\\\Rightarrow v=22.14741\ m/s

From continuity equation we have

Av=A_0v_0\\\Rightarrow A=\dfrac{A_0v_0}{v}\\\Rightarrow A=\dfrac{\pi 1.5^2\times 3.5}{22.14741}\\\Rightarrow A=1.11706\ cm^2

Fraction is given by

f=\dfrac{A_0-A}{A_0}\times 100\\\Rightarrow f=\dfrac{\pi 1.5^2-1.11706}{\pi 1.5^2}\times 100\\\Rightarrow f=84.196\ \%

The fraction is 84.196%

4 0
3 years ago
A negative charge -0.550 HC exerts an upward 0.700 N force on an unknown charge 0.220 m directly below it. (a) What is the unkno
Sonja [21]

Answer:

Part a)

q_2 = -6.8 \mu C

Part b)

F = 0.700 N

direction = downwards

Explanation:

As we know that the negative charge will experience the force due to some other charge below it

the force is given as

F = 0.700 N

now we know that

F = \frac{kq_1q_2}{r^2}

now plug in all data

0.700 = \frac{(9 \times 10^9)(0.550\mu C)q_2}{0.220^2}

0.700 = 1.022\times 10^5 q_2

q_2 = -6.8 \mu C

since this is a repulsion force so it must be a negative charge

Part b)

As per Newton's III law it will exert equal and opposite force on it

So here the force on the charge below it will be same in magnitude but opposite in direction

so here we have

F = 0.700 N

direction = downwards

4 0
3 years ago
The distance, measured from one edge of a black band to the same edge of the next band, is 5.0 cm. What additional information i
elena55 [62]

In order to find the average speed we will use the formula

v_{avg} = \frac{distance}{time}

now here we know that distance from one edge to other edge is given as

d = 5.00 cm

now in order to find the average speed as per the formula above we need to know the time taken from one edge to other edge

so using above equation

v = \frac{0.05}{\delta t}

here time can be found just by using the photo gates

If the photo gate will measure the time interval from one position to other then it will help to find the average speed

4 0
3 years ago
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