Answer:
Proxima Centauri
Explanation:
U 2 can help me by marking as brainliest........
It would take at least 20/9 seconds
Is that on the question or ?
For the question above, here is the equation to follow:
<span>F = mgsinα = Wsinα
=200 x 0.5 = 100 N
</span>OR
<span>Sin30 * 200N = 100 N
</span>
The asnwer is 100N. I hope this answer helps.
Answer:
.D.It will decrease because the charge will move in the direction of the electric field
Explanation:
<em>which there is a uniform electric field. (A uniform field is one whose strength and direction are the same at all points within the region.) What happens to the electric potential energy of the positive charge, after the charge is released from rest in the uniform electric field?A. It will remain constant because the electric field is uniform.B.It will decrease because the charge will move in the opposite direction of the electric field.C.It will remain constant because the charge remains at rest.D.It will decrease because the charge will move in the direction of the electric field.E.It will increase because the charge will move in the direction of the electric field.</em>
solution
The potential energy decreases, converted to kinetic energy
The charge will feel a force in the direction of the electric field (F=Eq) and thus it will accelerate with
a constant acceleration. (Just like releasing an object above the earth's surface - constant acceleration,
at least until it hits something.)
tus te answer will be
.D.It will decrease because the charge will move in the direction of the electric field
