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3 years ago

Please help !!!

1 answer:

3 0

Answer: 12 neutrons
Explanation: The mass number of an element tells us the number of protons AND neutrons in an atom (the two particles that have a measurable mass). Sodium has a mass number of 23amu. Since sodium has 11 protons, the number of neutrons must be 23 – 11 = 12 neutrons.

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Materials: • One disposable plastic cup • One disposable plastic spoon (plastic fork or knife may be used instead) • Thermometer

Leya [2.2K]

I'm not sure what the question is, this is a lab proecdure

4 0

3 years ago

Will the volume of a gas increase, decrease, or remain unchanged for each of the following sets of changes?

Katena32 [7]

The answer would be 150 half of 200 and 100 is 150

7 0

2 years ago

The compound adrenaline contains 56.7 % c, 6.56 % h, 28.37% o and 8.28 % n by mass. what is the empirical formula for adrenaline

-Dominant- [34]

Answer:- An empirical formula of adrenaline is $C_8H_1_1O_3N$ .

Solution:- Convert given percentages to moles and then calculate the mol ratio to get the simplest whole number ratio of moles of atoms which is the empirical formula of the compound.

$C=\frac{56.7}{12}$ = 4.725 mol

$H=\frac{6.56}{1}$ = 6.56 mol

$O=\frac{28.37}{16}$ = 1.773 mol

$N=\frac{8.28}{14}$ = 0.591 mol

let's calculate the mol ratio now. To calculate the mole ratio, we divide the moles of each by moleso f N as it's the least one:

$C=\frac{4.725}{0.591}$ = 8

$H=\frac{6.56}{0.591}$ = 11

$O=\frac{1.773}{0.591}$ = 3

$N=\frac{0.591}{0.591}$ = 1

So, an empirical formula of adrenaline is $C_8H_1_1O_3N$ .

3 0

3 years ago

The CN– ion is widely used in the synthesis of organic compounds. What is the pattern of electron pairs in this ion? How many bo

OleMash [197]

For the Lewis diagram of the cyanide ion, a figure is shown.<span>

There are 3 pairs of bonding electrons. There is a one lone pair each for the carbon and the nitrogen atoms.</span>

<span>I hope I was able to answer your question. Thank you!</span>

8 0

3 years ago

Liquid octane CH3CH26CH3 reacts with gaseous oxygen gas O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. If 2.80g

oee [108]

Answer:

54%

Explanation:

The balanced equation is:

$2 CH_{3}(CH_{2})_{6}CH_{3} + 25 O_{2} = 16 CO_{2} + 18 H_{2}O$

The first step is to determine the limiting reactant. For this, we calculate the moles of each given component and divide the result for the stoichiometric coefficient.

3.4 g octane / 114.23 g/mol = 0.030 mol octane

0.030 mol octane/2=0.015

5.9 g O2 / 32 g/mol = 0.18 mol O2

0.18 mol O2/25= 0.0074 mol

The lower number, in this case oxygen, is the limiting reactant. The value corresponds to the theoretical yield of the reaction.

Similarly, the real yield is calculated from the product.

2.80 g CO2/ 44.01 g/mol = 0.0636 mol CO2

0.0636 mol CO2/16 = 0.00398 mol

The percent yield is the ratio of the 2 multiplied by a hundred, then

Percent yield= 0.0398/0.0074 *100 = 54%

3 0

3 years ago