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scoray [572]
2 years ago
10

as you are talking to a friend on your cell phone, you might find that you can’t hear them because they are speaking very softly

. if you ask them to "speak up," from a physical perspective you are asking them to ________ of the sound waves they are producing.
Physics
1 answer:
GREYUIT [131]2 years ago
8 0

Answer: increase the amplitude

Explanation: it’s the correct answer

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What is the energy (in joules) of an ultraviolet photon with wavelength 110 nm?
Anon25 [30]

For light or ultraviolet, the formula for energy can be calculated using Planck’s equation. That is:

E =  h c / ʎ

where,

h is the Planck’s constant = 6.626 * 10^-34 m^2 kg / s

c is the speed of light = 3 * 10^8 m/s

ʎ is the wavelength of light = 110 nm = 110 x 10^-9 m

 

So calculating for energy E:

E = (6.626 * 10^-34 m^2 kg / s) * (3 * 10^8 m/s) / (110 x 10^-9 m)

E = 1.807 x 10^-18 J

5 0
3 years ago
By what factor is the intensity of sound at a rock concert louder than that of a whisper when the two intensity levels are 120 d
77julia77 [94]

Answer:

The intensity of sound at rock concert is  10¹⁰ greater than that of a whisper.

Explanation:

The intensity of sound is given by;

I(dB) = 10Log(\frac{I}{I_o} )

where;

I is the intensity of the sound

I₀ is the threshold of sound intensity = 1 x 10⁻¹² W/m²

The intensity of sound at a rock concert

120 = 10Log(\frac{I}{1*10^{-12}} )\\\\12 = Log(\frac{I}{1*10^{-12}} )\\\\\frac{I}{1*10^{-12}} = 10^{12}\\\\I = 1*10^{-12} *10^{12}\\\\I = 1*10^0\\\\I =1 \ W/m^2

The intensity of sound of a whisper

20 = 10Log(\frac{I}{1*10^{-12}} )\\\\2 = Log(\frac{I}{1*10^{-12}} )\\\\\frac{I}{1*10^{-12}} = 10^{2}\\\\I = 1*10^{-12} *10^{2}\\\\I = 1*10^{-10}\\\\I =10^{-10} \ W/m^2

Thus, the intensity of sound at rock concert is  10¹⁰ greater than that of a whisper.

4 0
3 years ago
What do you know about tides?
Neporo4naja [7]

Tides are the rise and fall of sea levels caused by the combined effects of the gravitational forces exerted by the Moon and the Sun, and the rotation of the Earth. Tide tables can be used to find the predicted times and amplitude (or "tidal range") of tides at any given locale.

For further expiation please contact me at 678-987-2411. Disclaimer(This is not a real number)

8 0
3 years ago
If the mass of an object were doubled, its acceleration due to gravity would be
svetoff [14.1K]
Unchanged because ALL objects fall at 9.8m/s^2. Yes, all
4 0
3 years ago
Read 2 more answers
A car was moving a 14 m/s. After 30 seconds, it’s speed increased to 20 m/s. What was its acceleration during this time?
Anuta_ua [19.1K]

Answer:

acceleration = 0.2 m/s/s

Explanation:

initial velocity u = 14

final velocity v = 20

time = 30

acceleration = ?

v = u + at

20 = 14 + 30a

30a = 6

a = 0.2 m/s/s

5 0
3 years ago
Read 2 more answers
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