Answer:
<em>The gap between the plates will be 1.2 x 10^-15 m</em>
<em>No, this is not practically achievable.</em>
Explanation:
Capacitance = 1.0 F
area of plate = 1.4 cm^2 = 1.4/10000 m^2 = m^2
distance = ?
We use the equation
= 
*ε
C is the capacitance
where A is the area
d is the distance of separation of plates
ε is the permeability of free space = 8.854×10^-12 F⋅m−1
substituting values, we have
1 = 
* 8.854×10^-12
distance between plates = <em>1.2 x 10^-15 m</em>
<em>This is not practically achievable in real life</em>
Answer:
8
Explanation:
The energy levels is given as
E(n) = n² * h² / ( 8 * m * L²), where
n = 1, 2, 3, 4,... etc
At ground state energy (n = 1), therefore is E(g) = h² / (8 * m * L²).
We can then say that
E(n) = n² * Eg
Therefore, to have E = 64 Eg, we must have n² = 64. And for n² to be equal to 64, we find the square root of n
n = √64
n = 8
Essentially, the needed quantum number is 8
Answer:
The total binding energy of the nucleus with 200 nucleons more than the total binding energy of the nucleus with 60 nucleons
Explanation:
Binding energy can be given by the formula:
Binding energy = Binding energy per nucleon * Number of nucleons
This means that if the binding energy per nucleon = x MeV
Where x is a positive real number
The nucleus with 60 nucleons will have Binding energy = 60x MeV
The nucleus with 200 nucleons will have binding energy = 200x MeV
For a +ve x, 200x > 60x
Answer:
The energy required is 12.887KJ
Explanation:
There are two separate heat inputs involved in this problem:
- q₁ = heat added to vaporize the methane at 109.1 K
- q₂ = energy added to heat the vapor from 109.1 K to 185.3 K
q = q₁ +q₂
q = nΔH + mCΔT
where;
n is number of moles of methane
ΔH is the molar enthalpy of vaporization of methane =8.17 kJ/mol
m is the mass of methane = 19g
C is the specific heat capacity of gaseous methane = 2.20 J/g.K
ΔT = T₂ - T₁ = 185.3 - 109.1 = 76.2 K
n = Reacting mass/Molar mass
molar mass of methane (CH₄) = 16g/mol
n = 19/16 = 1.1875 mol
⇒q₁ = nΔH = 1.1875 X 8.17 = 9.702 kJ
⇒q₂ = mCΔT, = 19 X 2.2 X 76.2 = 3185.16 J = 3.18516KJ
q = q₁ +q₂, ⇒ 9.702 kJ + 3.18516KJ = 12.887KJ
Therefore, the energy required is 12.887KJ
