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2 years ago

11

Explain how solar and lunar eclipse occur with the help of a labelled diagram.

2 answers:

snow_lady [41]2 years ago

8 0

Answer:

a solar eclipse occurs when the moon passes in front of the sun,blocking it out partially or completely. the eclipse results in parts of the earth being covered in the shadow of the moon. a lunar eclipse occurs when the moon passes directly behind earth and into its shadow.

Explanation:

Sindrei [870]2 years ago

8 0

Answer:

<em><u>a solar eclipse occurs when the moon passes in front of the sun,blocking it out partially or completely. the eclipse results in parts of the earth being covered in the shadow of the moon. a lunar eclipse occurs when the moon passes directly behind earth and into its shadow.</u></em>

<em>P</em><em>L</em><em>E</em><em>A</em><em>S</em><em>E</em><em> </em><em>M</em><em>A</em><em>R</em><em>K</em><em>.</em><em>.</em><em>.</em>

<em>A</em><em>R</em><em>I</em><em>A</em><em>♡</em>

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What is the meaning of viscosity?

Vera_Pavlovna [14]

the state of being thick, sticky, and semifluid in consistency, due to internal friction.

5 0

2 years ago

plates of a parallel-plate capacitor are 2.50 mm apart, and each carries a charge of magnitude 85.0 nC . The plates are in vacuu

tensa zangetsu [6.8K]

Answer:

12500 V

Explanation:

The electric field in the gap of a parallel-plate capacitor is uniform, so the following relationship between electric field strength, potential difference and distance can be used:

$\Delta V = E d$

where

$\Delta V$ is the potential difference between the plates

E is the electric field strength

d is the distance between the plates

For the capacitor in this problem, we have

$E=5.00\cdot 10^6 V/m$

$d = 2.50 mm = 2.50\cdot 10^{-3} m$

Substituting, we find

$\Delta V = (5.00\cdot 10^6)(2.50\cdot 10^{-3})=12500 V$

3 0

3 years ago

What is the equivalent unit to a newton?

allsm [11]

My science teacher said that there is no equivalent unit to a newton

6 0

3 years ago

Read 2 more answers

A litre of a gas weigh 2 gram at 300 kelvin temperature and 1 atm pressure,if the pressure is made 75 atm then at which temperat

liberstina [14]

Answer:

45000 K .

Explanation:

Given :

A liter of a gas weigh 2 gram at 300 kelvin temperature and 1 atm pressure

We need to find the temperature in which 1 litre of the same gas weigh 1 gram

in pressure 75 atm.

We know, by ideal gas equation :

$PV=nRT$

Here , n is no of moles , $n=\dfrac{Given \ Weight }{Molecular\ Mass}=\dfrac{w}{M}$

Putting initial and final values and dividing them :

$\dfrac{P_1V_1}{P_2V_2}=\dfrac{\dfrac{w_1}{M}T_1}{\dfrac{w_2}{M}T_2}$

$\dfrac{1\times 1}{75\times 1}=\dfrac{\dfrac{2}{M}\times 300}{\dfrac{1}{M}\times T_2}\\ \\T_2=45000\ K.$

Hence , this is the required solution.

7 0

3 years ago

A conducting loop has an area of 0.065 m2 and is positioned such that a uniform magnetic field is perpendicular to the plane of

aev [14]

Answer:

initial magnetic field 1.306 T

Explanation:

We have given area of the conducting loop $A=0.065m^2$

Emf induced = 1.2 volt

Initial magnetic field B = 0.3 T

Time dt = 0.087 sec

We know that induced emf is given by $e=\frac{d\Phi }{dt}=-A\frac{db}{dt}$

$1.2=0.065\times \frac{db}{0.087}$

$db=1.606T$

So initial magnetic field = 1.606-0.3= 1.306 T

5 0

2 years ago