A kind of prose writing in which the writer explains information is called _____. exposition illustrative writing propaganda vig
1 answer:
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Here in first case both balls will exert electrostatic force on each other
due to this electrostatic force the two balls will repel each other
Apart from this there will be gravitational force on the two balls which is vertically downwards
Now here we know that as the electrostatic force of repulsion will increase between two balls then the angle between the two balls will be more as the horizontal force will separate the two balls
Part b)
As we decrease the charge on one ball then the net electrostatic force between two balls will decrease as we know that this force will depends on the product of two charges
so here the angle between the two balls will decrease and the two balls will come closer.
Also by the free body diagram of two balls we can see that all the forces on the balls are same so the angle made by the ball with the vertical is same for both the balls
so here the angle that ball l makes with the vertical will be equal to the angle that ball 2 makes with the vertical.
Answer : The heat of sublimation of Li(s) is 179.5 kJ/mole
Explanation :
The formation of lithium iodide is,
= enthalpy of formation of lithium iodide
The steps involved in the born-Haber cycle for the formation of :
(1) Conversion of solid lithium into gaseous lithium atoms.
= sublimation energy of lithium
(2) Conversion of gaseous lithium atoms into gaseous lithium ions.
= ionization energy of lithium
(3) Conversion of molecular gaseous iodine into gaseous iodine atoms.
= dissociation energy of iodine
(4) Conversion of gaseous iodine atoms into gaseous iodine ions.
= electron affinity energy of iodine
(5) Conversion of gaseous cations and gaseous anion into solid lithium iodide.
= lattice energy of lithium iodide
To calculate the overall energy from the born-Haber cycle, the equation used will be:
Now put all the given values in this equation, we get:
Therefore, the heat of sublimation of Li(s) is 179.5 kJ/mole