<u>Answer:</u>
The correct answer option is momentum.
<u>Explanation:</u>
Momentum is the product of an object's mass and velocity.
It is a term which describes the relationship between the mass of an object and the velocity of an object.
Momentum can be represented in the form of an equation as:
P = mv
where P is the momentum,
m is the mass of the object; and v is the velocity of that object.
According to Newton, an object will only accelerate if there is a net or unbalanced forceacting upon it. The presence of an unbalanced force will accelerate an object - changing its speed, its direction, or both its speed and direction.
<h3>Question -:</h3>
The Earth orbits around the sun because the gravitational force that the sun
exerts on the Earth:
O A. causes Earth's acceleration toward the sun.
O B. is very small because the sun is so far from the Earth.
O c. is smaller than the force the Earth exerts on the sun.
O D. pushes the Earth away from the sun.
<h3>Answer -:</h3>
O A. causes Earth's acceleration toward the sun.
<em>I </em><em>hope </em><em>this</em><em> </em><em>helps</em><em>,</em><em> </em><em>have </em><em>a </em><em>nice </em><em>time </em><em>ahead!</em>
<span>Ocean currents act much like a conveyer belt,
transporting warm water and precipitation from the equator toward the
poles and cold water from the poles back to the tropics. Thus, currents
regulate global climate, helping to counteract the uneven distribution of solar radiation reaching Earth's surface.</span>
-17.555m/s
first I found the time it took for jacks stone to reach the bottom, using the formula vf = vi + at, vf and vi are final and initial velocities.
then i found the velocity at 6.6m using vf^2 = vi^2 + 2ad
and I found the time it took to get to 6.6m, so that I knew how long Jill waited to throw her stone, I used the formula d = t(vi+vf)/2, then i done total time - the time she waited, to get the time it took for there stones to hit the ground at the same time.
then to find the initial velocity of her throw I used the formula d = vit + (at^2)/2
