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Ratling [72]
3 years ago
15

A force is applied to a 2.9 kg mass and pro-

Physics
1 answer:
adoni [48]3 years ago
3 0

Answer:

5.8 or 5.77

Explanation:

I'm not sure

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What does it mean that corporations are taxed twice
jolli1 [7]
Many people have herd that corporate income is taxed twice: once to the corporation itself and then a second time when earnings are paid out to the corporation's owners the reason is simple: shareholders rarely pay themselves dividends
4 0
4 years ago
A 1520 kg car is rolling<br> down a frictionless<br> 14.4° slope. What is<br> its acceleration?
Umnica [9.8K]

Answer:

a = 2.44 m/s²

Explanation:

The Net force acting on the car downwards the plane will be equal to the component of the weight that is parallel to the plane.

Thus;

mg(sin θ) = ma

Thus;. g(sin θ) = a

g is acceleration due to gravity = 9.81 m/s²

θ = 14.4°

Thus;

9.81 × sin 14.4 = a

a = 2.44 m/s²

7 0
3 years ago
A man is at a car dealership, looking for a car to buy. He looks at the sticker on the driver’s window of a car and sees that th
maxonik [38]

Answer:

he will see the sticker because its behind a window bruh and thats a big daddy stack of greens

Explanation:

3 0
3 years ago
The magnitude of the magnetic field B a distance r from a long straight wire is B = μ 0 I 2 π r where μ 0 is the permeability co
PSYCHO15rus [73]

Answer:

The magnetic field is lowest for largest distance and highest when distance is least.

Explanation:

The magnitude of magnetic field strength at a distance 'r' from a long straight wire carrying current 'I' is given as:

B=\frac{\mu_0 I}{2\pi r}\\Where,\mu_0\to permeability\ constant\ of\ free\ space

Now, as per question, the distance 'r' is varied while keeping the current constant in the wire.

As seen from the above formula, the magnitude of magnetic field strength for a constant current varies inversely with the distance 'r'. This means that, as the value of 'r' increases, the magnitude of magnetic field strength decreases and vice-versa.

Therefore, the magnitude of magnetic field strength is maximum when the distance 'r' is least and the magnetic field is minimum for the largest distance.

Example:

If B_1, B_2,\ and\ B_3 are the magnitudes of magnetic field strengths for distances r_1,r_2, \ and\ r_3 respectively such that r_1. Now, as per the explanation above, the order of magnitudes of magnetic field strength is:

B_1>B_2>B_3

6 0
4 years ago
•• Your roommate is working on his bicycle and has the bike upside down. He spins the 60-cm-diameter wheel, and you notice that
Y_Kistochka [10]

Answer:

v=0.57\frac{m}{s}

a_c=10.83\frac{m}{s^2}

Explanation:

We have an uniform circular motion, therefore, the pebble’s speed is given by the distance traveled in a revolution (2\pi r) and the period (T), since this is the time pebble’s takes to complete a revolution:

v=\frac{2\pi r}{T}

The period is inversely proportional to the frequency:

T=\frac{1}{f}

So, we have:

v=\frac{2\pi r}{\frac{1}{f}}\\v=2\pi rf\\

Recall that the radius is the half of the diameter and one revolution per is equal to one Hz:

v=2\pi (30*10^{-2}m)(3Hz)\\v=0.57\frac{m}{s}

The centripetal acceleration is defined as:

a_c=\frac{v^2}{r}\\a_c=\frac{(0.57\frac{m}{s})^2}{30*10^{-2}m}\\\\a_c=10.83\frac{m}{s^2}

6 0
3 years ago
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