X^2 - y^2 - 2x + 6y - 8
<span>= (x^2 - 2x + 1) - (y^2 - 6y + 9) - 8 - 1 + 9 </span>
<span>= (x - 1)^2 - (y - 3)^2 </span>
<span>= [(x - 1) - (y - 3) ] [(x - 1) + (y - 3)] </span>
<span>= (x - 1 - y + 3) ( x - 1 + y - 3) </span>
<span>= (x - y + 2) (x + y - 4)</span>
Answer:
D
Step-by-step explanation:
Any other product in Quadrant IV will be negative also, so Quadrant IV is part of my answer. The points (x, y), with xy < 0, lie in Quadrants II and IV.
The answer should be 4, 4 can go into all of these numbers
Answer: 62.5 percent
Step-by-step explanation:
Answer:
See explanation
Step-by-step explanation:
