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Bezzdna [24]
3 years ago
13

How do interest groups and PACs keep us from

Physics
1 answer:
levacccp [35]3 years ago
3 0

Answer:

Interest groups help democracy because they represent the interests of such large numbers of people and encourage political participation by many groups. The stable, cooperative relationship often develops among a congressional committee, an administrative agency, and one or more supportive interest groups.

Interest groups try to influence the government to adopt legislation that would benefit them. Email, letter, faxes, phone calls, providing research and information (to bring about change by proving your cause with facts by funded research).

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A 4kg block sitting on the floor, how much potential energy does it have?
prohojiy [21]

Well, there you have a very important principle wrapped up in that question.

There's actually no such thing as a real, actual amount of potential energy.
There's only potential <em><u>relative to some place</u></em>.  It's the work you have to do
to lift the object from that reference place to wherever it is now.  It's also
the kinetic energy the object would have if it fell down to the reference place
from where it is now.

Here's the formula for potential energy:    PE = (mass) x (gravity) x (<em><u>height</u></em><u>)</u> .

So naturally, when you use that formula, you need to decide "height above what ?"

If you're reading a book while you're flying in a passenger jet, the book's PE is
(M x G x 0 meters) relative to your lap, (M x G x 1 meter) relative to the floor of the
plane, (M x G x 10,000 meters) relative to the ground, and maybe (M x G x 25,000 meters)
relative to the bottom of the ocean.

Let's say that gravity is 9.8 m/s² .

Then a 4kg block sitting on the floor has (39.2 x 0 meters) PE relative to the floor
it's sitting on, also (39.2 x 3 meters) relative to the floor that's one floor downstairs,
also (39.2 x 30 meters) relative to 10 floors downstairs, and if it's on the top floor of
the Amoco/Aon Center in Chicago, maybe (39.2 x 345 meters) relative to the floor
in the coffee shop that's off the lobby on the ground floor. 

3 0
3 years ago
Read 2 more answers
2. A test reveals that 150 J of work is required to lift an object 3 m at a
Nuetrik [128]

Answer:

50N

Explanation:

W=Fd

150=F(3)

50N=F

7 0
3 years ago
You read in a science magazine that on the Moon, the speed of a shell leaving the barrel of a modern tank is enough to put the s
olga_2 [115]

To solve this problem we will use the definition of the kinematic equations of centrifugal motion, using the constants of the gravitational acceleration of the moon and the radius of this star.

Centrifugal acceleration is determined by

a_c = \frac{v^2}{r}

Where,

v = Velocity

r = Radius

From the given data of the moon we know that gravity there is equivalent to

a = 1.62m/s

While the radius of the moon is given by

r = 1.74*10^6m

If we rearrange the function to find the speed we will have to

v = \sqrt{ar}

v = \sqrt{1.6(1.74*10^6)}

v = 1.7km/s

The speed for this to happen is 1.7km/s

3 0
3 years ago
Which system works with the respiratory system for the exchange of gases to take place?
zvonat [6]

Answer:

Circulatory System

Explanation:

The respiratory system works with the circulatory system to provide tis oxygen and to remove the waste products of metabolism. It also helps to regulate PH of the blood. Respiration is the sequence of events that result in the exchange of oxygen and carbon dioxide between the atmosphere and the body cells.

7 0
3 years ago
Shane is riding his bike at a speed of 10m/s. He isn't watching carefully where he is going and almost hit a tree. He abruptl
Rom4ik [11]

Answer:

2.5m/s²

Explanation:

a = v/t

Where;

V = velocity (m/s)

a = acceleration (m/s²)

t = time (s).

According to the information provided in this question,

a = ?

v = 10m/s

t = 4

a = 10/4

a = 2.5m/s²

4 0
3 years ago
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