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Bezzdna [24]
3 years ago
13

How do interest groups and PACs keep us from

Physics
1 answer:
levacccp [35]3 years ago
3 0

Answer:

Interest groups help democracy because they represent the interests of such large numbers of people and encourage political participation by many groups. The stable, cooperative relationship often develops among a congressional committee, an administrative agency, and one or more supportive interest groups.

Interest groups try to influence the government to adopt legislation that would benefit them. Email, letter, faxes, phone calls, providing research and information (to bring about change by proving your cause with facts by funded research).

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AHH please help-
umka2103 [35]

Answer:

Radiation

Explanation:

I hope that help's

5 0
3 years ago
It is dangerous to stand near the railway leak when train passing by,why?​
4vir4ik [10]

Answer:

Because a person may be pulled in the direction of the moving train. Thereby causing accident

Explanation:

According to Daniel Bernoulli's theorem, he was widely known as a Mathematician. He stated that due to the higher velocity of a moving train, there is higher kinetic energy in terms of volume around it, while the air pressure between the person and the train becomes lower.

As a result, a person near a moving train may be pulled in the direction of the moving train. Thereby causing accidents that may lead to death.

3 0
3 years ago
Need help anybody thanks
mars1129 [50]
If there are no windows, then the illumination in the room depends
only on the room and what's in it, not on anything outside. 
The time of day has no effect.  The other things all do. 
4 0
3 years ago
This famous scientist conducted experiments that led to the development of the Plum Pudding atomic model.
s344n2d4d5 [400]
J.J. Thomson discovered the electron, leading to the Plum Pudding model
5 0
3 years ago
Read 2 more answers
A circular loop of wire with a radius of 20 cm lies in the xy plane and carries a current of 2 A, counterclockwise when viewed f
Zina [86]

To solve this problem we will apply the concept related to the magnetic dipole moment that is defined as the product between the current and the object area. In our case we have the radius so we will get the area, which would be

A=\pi r^2

A =\pi (0.2)^2

A =0.1256 m^2

Once the area is obtained, it is possible to calculate the magnetic dipole moment considering the previously given definition:

\mu=IA

\mu=2(0.1256)

\mu=0.25 A\cdot m^2

Therefore the magnetic dipole moment is 0.25A\cdot m^2

6 0
3 years ago
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