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3 years ago

If 128 v is required to push 4.00 A of current though a resistor, what is the resistance

Physics

1 answer:

prisoha [69]3 years ago

8 0

Answer:

32.0 Ω

Explanation:

Ohm's law:

V = IR

128 V = (4.00 A) R

R = 32.0 Ω

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A 24-gauge copper wire has a diameter of 0.51 mm and is used to connect a speaker to an amplifier. The speaker is located 8.5 m

Sergeu [11.5K]

Given Information:

Diameter of the wire = d = 0.51 mm

Length of the wire = L = 8.5 m

Resistance of the speaker = Rsp = 8 Ω

Required Information:

Part A: Resistance of the connecting wire = R = ?

Part B: Ratio of the resistance of connecting wire and speaker = ?

Answer:

Part A: R = 1.43 Ω

Part B: R is 17.8% of Rsp

Explanation:

R = ρL/A

where ρ is the resistivity of the copper wire 1.72x10⁻⁸ Ω/m (at 20 ˚C)

A is the area of the copper wire A = πr²

r = d/2 = 0.51/2 = 0.255 = 0.0255 cm 0.000255 m

Part A: What is the minimum resistance of the connecting speaker wires at 20 ˚C?

R = ρL/πr

R = 1.72x10⁻⁸(8.5)/π*(0.000255)²

R = 0.715 Ω

Since two connecting wires are needed so total resistance becomes

R = 2*715 = 1.43 Ω

Part B: Compare the resistance of the wire to the resistance of the speaker (RSP = 8 Ω)

Resistance of connecting wires = 1.43 Ω

Resistance of the speaker = 8 Ω

1.43/8 = 0.178 = 17.8 %

Therefore, resistance of the connecting wires is 17.8% of the speaker resistance.

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4 years ago

Which quantity is a vector quantity?

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Answer:

displacement is a vector quantity

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3 years ago

What is gravitational field intensity?

mezya [45]

<h3>Answers :</h3>

The gravitational field intensity (EG) or (g) is the force on a unit mass at a point in the field.

Since the force (F) on a body of mass m in a gravitational field of a body of mass M = GMm/r2 .

you can see that the force per unit mass is given by F/m. So:

Gravitational Field Intensity (EG) = (g) = F/m = GM/r2

The units for EG are N kg -1 or since F = ma, F/m = a and so EG may be expressed in ms -2

Hope this will help you :))

Do give this answer a brainliest :D

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3 years ago

The surface of the paper is phosphorescent. When light shines on it, some of the energy is absorbed and re-emitted slowly over t

Ad libitum [116K]

Answer:

Explanation:

Recall that the hierarchy of wavelength color from minimum wavelength to maximum wavelength is:

$V < I < B < G < Y < O < R;$ and

$E \ \alpha \ \dfrac{1}{\lambda}$

As a result, blue light has a higher energy level than green and red light.

As a result, the surface glows due to the blue LED. The green LED, on the other hand, would not allow the surface to glow as much as the red LED, which has a lower energy level when compared to the green light. As a result, the red LED would not allow the surface to glow as well.

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Which statement or question is a good hypothesis

Kisachek [45]

I’m pretty sure it’s A)

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