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Novay_Z [31]
2 years ago
7

Kinetic friction is always

Physics
2 answers:
BARSIC [14]2 years ago
7 0
  • Kinetic friction is always <u>D.</u><u> </u><u>less than limiting static friction</u><u>.</u>

<u>Remember</u><u> </u><u>=</u><u>></u><u> </u>

  • <em>Rolling </em><em>Friction</em><em> </em><em><</em><em> </em><em>Sliding</em><em>/</em><em>Kinetic</em><em> </em><em>Friction</em><em> </em><em><</em><em> </em><em>Static </em><em>Friction</em><em>.</em>
zhenek [66]2 years ago
3 0
D.less than limiting static friction
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Select the correct locations on the image.
RideAnS [48]

Answer:

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Explanation:

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3 years ago
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Suppose we hang a heavy ball with a mass 13 kg (so the weight is ) from a steel wire 3.9 m long that is 3.1 mm in diameter (radi
Katena32 [7]

Answer:

1.635×10^-3m

Explanation:

Young modulus is the ratio of the tensile stress of a material to its tensile strain.

Young modulus = Tensile stress/tensile strain

Tensile stress = Force/Area

Given force = 130N

Area = Πr² = Π×(1.55×10^-3)²

Area = 4.87×10^-6m²

Tensile stress = 130/4.87×10^-6 = 8.39×10^7N/m²

Tensile strain = extension/original length

Tensile strain = e/3.9

Substituting in the young modulus formula given young modulus to be 2×10¹¹N/m²

2×10¹¹N/m² = 8.39×10^7/{e/3.9)}

2×10¹¹ = (8.39×10^7×3.9)/e

2×10¹¹e = 3.27×10^8

e = 3.27×10^8/2×10¹¹

e = 1.635×10^-3m

The stretch of the steel wire will be

1.635×10^-3m

7 0
3 years ago
How much force is applied if a 130kg mass is accelerated at 5 m/s^2?​
STALIN [3.7K]

Answer:

650N

Explanation:

f= ma

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5 0
3 years ago
Why is Earth’s North Pole a geographic north pole but a south seeking pole magnetically?
natima [27]

Answer:It is actually the South Magnetic pole

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3 years ago
A 3.0-kg block moves up a 40o incline with constant speed under the action of a 26-N force acting up and parallel to the incline
CaHeK987 [17]

Answer:

it is very hard question for me sorry i cant solve it

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3 years ago
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