Mass, m=22 kg
It is given that Force, F = 88N
Acceleration, a=4 m/s 2
We want to find how much momentum the dumbbell has at the moment it strikes the floor. Let's use this kinematics equation:
Vf² = Vi² + 2ad
Vf is the final velocity of the dumbbell, Vi is its initial velocity, a is its acceleration, and d is the height of its fall.
Given values:
Vi = 0m/s (dumbbell starts falling from rest)
a = 10m/s² (we'll treat downward motion as positive, this doesn't affect the result as long as we keep this in mind)
d = 80×10⁻²m
Plug in the values and solve for Vf:
Vf² = 2(10)(80×10⁻²)
Vf = ±4m/s
Reject the negative root.
Vf = 4m/s
The momentum of the dumbbell is given by:
p = mv
p is its momentum, m is its mass, and v is its velocity.
Given values:
m = 10kg
v = 4m/s (from previous calculation)
Plug in the values and solve for p:
p = 10(4)
p = 40kg×m/s
About 2 to 5 centimeters per year (1 to 2 inches per year), about the same speed that your fingernails grow. Therefore, the statement is false
Answer:
When the compass is placed below the wire, and the electric current switched on, the needle deflects in the opposite direction. If an electric current is passed through a long coil of wire (a solenoid ) a magnetic field is produced which is the same shape as that of a bar magnet.
Explanation:
If im correct the answer is gravity
and wind resistance if you lift it fast
~~~hope this helps~~~
~~davatar~~
