Ask question

Ask question

All categories

3 years ago

14

Which explanations did you include in your response? Check all that apply. The oxidation number of carbon changes from -1 to +4.

The oxidation number of oxygen changes from 0 to -2. Carbon is oxidized. Oxygen is reduced. Electrons are transferred from carbon to oxygen.

1 answer:

Kaylis [27]3 years ago

5 0

Answer:

B, E

Explanation:

Edge

You might be interested in

What happens when a catalyst is used in a reaction?.

den301095 [7]

A catalyst is a substance that increases the rate of a chemical reaction by lowering the activation energy without being used up in the reaction. After the reaction occurs, a catalyst returns to its original state and so catalysts can be used over and over again.

6 0

2 years ago

If one gram of sulphur dioxide contains x molecules what will be the number of molecules in 1g of methane

evablogger [386]

The ratio of molecules in sulphur dioxide and methane will be the same as the ratio of their moles. So, first of all we should find out the number of moles of sulphur dioxide in 1 gram of sulphur dioxide in 1 gram of sulphur dioxide, and the number of moles of methane in 1 gram of methane. This can be done as follows :

(i) The molecular formula of sulphur dioxide is $SO_{2}$

So, $1$ mole of $SO_{2}$ = $Mass$ $of$ $2'O'$

$=32+2*16$

$= 64$ grams

Now, $64g$ of sulphur dioxide $= 1$ mole

So, $1g$ of sulphur dioxide = $\frac{1}{64}$ mole

Thus, we have $\frac{1}{64}$ mole of sulphur dioxide and it contains molecules in it. Now, since equal moles of all the substance contain equal number of molecules, therefore, $\frac{1}{64}$ mole of methane will also contain x molecules of methane.

(ii) Molecular formula of methan is $CH_{4}$

So, 1 mole of $CH_{4}$ = Mass of C + Mass of 4 H

$=12+4*12$

Now, 16g of methane = 1 mole

So, 1 g of mathane = $\frac{1}{16}$ mole

We know that:

$\frac{1}{64}$ mole of methane contains = x molecules

So, $\frac{1}{16}$ mole of contains will contain = $\frac{x*64}{16}$ molecules

= $4x$ molecules

7 0

2 years ago

PLEASE HELP ON MY FINAL

svet-max [94.6K]

Answer:

The answer is D- creation of atmospheric systems that provide oxygen while absorbing carbon dioxide

Explanation:

By using elimination of choice that answer seems the most accurate.

4 0

2 years ago

Jason combines the two intermediate steps shown. 2 equations. First: upper N subscript 2 (g) plus upper O subscript 2 (g) right

zhenek [66]

Answer:

The molecules of oxygen should be placed as reactants in the equation.

Explanation:

1: N₂ + O₂ → 2NO

2: 2NO + O₂ → 2NO₂

complete reaction:

N₂ + 2O₂ → 2NO₂

In both intermediate equations' oxygen is used as reactant because the end product is the product of the combination of nitrogen and oxygen. So in the complete or overall reaction, oxygen should also be placed as reactant.

We can not place oxygen at the side of products neither we can cancel it because, products can only be obtained at the end of the reaction but according to the equations' oxygen is not the end product of the reaction. But the addition into the reaction (Eq. 2) to make the new product.

Also, we can not cancel it because to cancel out molecules of oxygen should be present at the both sides with same amount in the stoichiometric equation.

Hence, in a balanced chemical equation, oxygen should be written as a reactant by using the correct number of moles.

3 0

3 years ago

A student is using colored beads to model 1 molecule of LaTeX: Ca_3\left(PO_4\right)_2C a 3 ( P O 4 ) 2. The student uses blue b

stich3 [128]

Answer:

3 blue beads

1 red beads

4 green beads

Explanation:

The compound given:

Ca₃PO₄

Elements in the compound are:

Ca

P

O

Number of atoms are :

Ca - 3

P - 1

O - 4

blue beads to model Calcium

red beads to model Phosphorus

green beads to model Oxygen

3 blue beads

1 red beads

4 green beads

5 0

3 years ago