Ask question

Ask question

All categories

2 years ago

14

Which explanations did you include in your response? Check all that apply. The oxidation number of carbon changes from -1 to +4.

The oxidation number of oxygen changes from 0 to -2. Carbon is oxidized. Oxygen is reduced. Electrons are transferred from carbon to oxygen.

1 answer:

Kaylis [27]2 years ago

5 0

Answer:

B, E

Explanation:

Edge

You might be interested in

Air, with an initial absolute humidity of 0.016 kg water per kg dry air, is to be dehumidified for a drying process by an air co

amid [387]

Answer:

(a) The proportion of dry air bypassing the unit is 14.3%.

(b) The mass of water removed is 1.2 kg per 100 kg of dry air.

Explanation:

We can express the proportion of air that goes trough the air conditioning unit as $p_{d}$ and the proportion of air that is by-passed as $p_{bp}$ , being $p_{d}+p_{bp}=1$ .

The amount of water that goes into the drier inlet has to be 0.004 kg/kg, and can be expressed as:

$0.004 = 0.016*p_{bp}+ 0.002*p_{d}$

Replacing the first equation in the second one we have

$0.004 = 0.016*(1-p_{d})+ 0.002*p_{d}=0.016-0.016*p_{d}+0.002*p_{d}\\0.004 - 0.016 = (-0.016+0.002)*p_{d}\\-0.012 = -0.014*p_{d}\\p_{d}=\frac{-0.012}{-0.014}=0.857\\\\p_{bp}=1-p_{d}=1-0.857=0.143$

(b) Of every kg of dry air feed, 85.7% goes in to the air conditioning unit.

It takes (0.016-0.002)=0.014 kg water per kg dry air feeded.

The water removed of every 100 kg of dry air is

$100 kgDA*0.857*0.014 kgW/kgDA= 1.1998 \approx 1.2 kgW$

It can also be calculated as the difference in humiditiy between the inlet and the outlet: (0.016-0.004=0.012 kgW/kDA) and multypling by the total amount of feed (100 kgDA).

100 * 0.012 = 1.2 kgW

7 0

3 years ago

Plz help!!! Will give brainsiest!!!!

Olenka [21]

H2SO4+2KOH->K2SO4+2H2O

3 0

3 years ago

What is the name of the compound CH4?*

solmaris [256]

Answer:

Methane

Explanation:

Methane is a synthetic compound with the substance recipe CH4. It is a gathering 14 hydride and the most straightforward alkane, and is the principle constituent of petroleum gas

6 0

3 years ago

The gas that a diver breathes must be maintained at a partial pressure of 0.20 atm of oxygen. More oxygen could poison the diver

Nimfa-mama [501]

<u>Answer:</u> The partial pressure of helium gas is 0.80 atm

<u>Explanation:</u>

Dalton's law of partial pressure states that the total pressure of the system is equal to the sum of partial pressure of each component present in it.

To calculate the partial pressure of helium gas, we use the law given by Dalton, which is:

$P_T=p_{He}+p_{O_2}$

We are given:

Total pressure of the cylinder, $P_T$ = 1.00 atm

Vapor pressure of oxygen gas, $p_{O_2}$ = 0.20 atm

Putting values in above equation, we get:

$1.00=p_{He}+0.20\\\\p_{He}=1.00-0.20=0.80atm$

Hence, the partial pressure of helium gas is 0.80 atm

5 0

3 years ago

The type of decay associated with the emission of a photon is

kvasek [131]

<u>Gamma Decay</u> in the nucleus is similar to <u>Photon Decay </u>in atoms. When a electron charges energy levels in the atoms, it desposes of photon (with energy of order electron volts).

8 0

2 years ago